- #1

Rectifier

Gold Member

- 313

- 4

**The problem statement**

ln(x) = 5 -x

*Solve for x.*

**The attempt at a solution**

[tex]ln x = 5 - x \\ e^{ln x} = e^{5 - x} \\ e^{ln x} = \frac{e^5}{e^x} \\ x e^x = e^5[/tex]

Here is the place where I get stuck.