LU Decomposition: Calculating Determinant of Square Matrix (Example Included)

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The discussion focuses on calculating the determinant of a square matrix using LU Decomposition. It emphasizes that the determinant can be computed efficiently by utilizing the relationship det(A) = det(L) det(U), where L is a unit triangular matrix and U is an upper triangular matrix. The determinant of matrix A is derived from the product of the diagonal entries of matrix U. A clear example and methodology are provided to illustrate this process, ensuring that even those unfamiliar with technical terms can grasp the concept.

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How would I calculate the determinant of a square matrix using LU Decomposition. Please be plain, I am not good with technical terms. An example would be nice. Thank you!
 
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Hello,

I looked up a nice example on how to compute LU Decomposition. On this http://www.utdallas.edu/dept/abp/PDF_Files/LinearAlgebra_Folder/LU_Decomposition.pdf" , the author has provided a nice clear explanation on how to do an LU decomposition (I've also attached the pdf, in case the link is taken down).

And according to http://en.wikipedia.org/wiki/LU_decomposition#Determinant"
The matrices L and U can be used to compute the determinant of the matrix A very quickly, because det(A) = det(L) det(U) and the determinant of a triangular matrix is simply the product of its diagonal entries. In particular, if L is a unit triangular matrix, then
[tex]det(A) = det(L)det(U) = 1 \cdot det(U) =\prod^{n}_{i = 1}u_{ii}.[/tex]
(Note: A http://planetmath.org/encyclopedia/UnitLowerTriangularMatrix.html" is a triangular matrix with 1's along it's diagonals)

So if you used the methodology to get an LU decomposition and further reduce the L matrix to a lower triangular matrix with 1's along the diagonal- then you can simply take the product of the diagonals of the right upper triangular matrix U to get your determinant for matrix A.
 

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