Magnetic field and Bainbridge mass spectrometer

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SUMMARY

The discussion focuses on calculating the mass of a singly charged selenium ion using the Bainbridge mass spectrometer's parameters. The electric field is specified at 1.05 x 105 V/m, and the magnetic field strength is 0.520 T. The radius of the ion's circular path is 31.0 cm. The relevant equation used is B = mv/qr, where B is the magnetic field, m is the mass, v is the velocity, q is the charge, and r is the radius of the path. The mass number of the selenium isotope is determined by rounding the mass in atomic mass units to the nearest integer.

PREREQUISITES
  • Understanding of the Bainbridge mass spectrometer principles
  • Familiarity with the relationship between electric and magnetic fields
  • Knowledge of the equation B = mv/qr
  • Basic concepts of atomic mass units (u)
NEXT STEPS
  • Calculate the velocity of the selenium ion using the electric field and magnetic field values
  • Explore the derivation of the mass from the equation B = mv/qr
  • Research the properties of selenium isotopes and their mass numbers
  • Investigate the applications of Bainbridge mass spectrometers in modern chemistry
USEFUL FOR

This discussion is beneficial for physics students, chemists, and researchers interested in mass spectrometry and ion behavior in magnetic fields.

Clement
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Homework Statement


The electric field between the plates of the velocity selector in a Bainbridge mass spectrometer is 1.05 105 V/m, and the magnetic field in both regions is 0.520 T. A stream of singly charged selenium ions moves in a circular path with a radius of 31.0 cm in the magnetic field. Determine the mass of one selenium ion.

Determine the mass number of this selenium isotope. (The mass number is equal to the mass of the isotope in atomic mass units, rounded to the nearest integer. One atomic mass unit = 1 u = 1.66 10-27 kg.)

Homework Equations


B=mv/qr


The Attempt at a Solution


used formula E= kq/r^2 and found a q, but it says the particles are positively charged,
dont know how to continue without the velocity.
 
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got it, thanks!
 

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