How Does Proton Spin Influence Its Magnetic Field?

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SUMMARY

The discussion centers on the relationship between proton spin and its magnetic field, specifically addressing the magnetic moment of hydrogen, which is approximately 2.79284734 magnetons. A calculation is presented suggesting that rotating a proton with 150 keV could theoretically generate a magnetic field of 928 megateslas. Participants clarify that the magnetic moment of a proton is not zero and emphasize the challenges of aligning protons due to thermal motion and external shielding effects. The conversation also highlights the need for mathematical prefactors in calculations related to atomic spin and momentum.

PREREQUISITES
  • Understanding of nuclear magnetic moments
  • Familiarity with proton spin and magnetic dipoles
  • Basic knowledge of energy calculations in electronvolts (eV) and joules
  • Proficiency in using Excel for scientific calculations
NEXT STEPS
  • Research the mathematical derivation of nuclear magnetic moments
  • Study the effects of temperature on proton alignment in magnetic fields
  • Explore the concept of electric dipole moments in protons
  • Learn about the internal structure of protons and their magnetic properties
USEFUL FOR

This discussion is beneficial for physicists, nuclear scientists, and students studying atomic physics, particularly those interested in the magnetic properties of protons and their applications in magnetic resonance imaging (MRI) and particle physics.

Javier Lopez
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I do not understand the theory of moment of nuclei

I read here: http://www.sjsu.edu/faculty/watkins/nuclearmoment3.htm that the magnetic moment of Hydrogen is 2.79284734 magnetons = 2.79284734*9.274009994e-24 joules/tesla =2.59e-23 joules/tesla
So if I make to rotate a proton using 150 keV could I have a magnetic field at the proton surface accordingly following expresion?
$$\frac{150keV*1.6022*10^{-16}\frac{Joule}{keV}} {2.59*10{-23}\frac{Joules}{tesla}}=928 megateslas$$

Do I have to multiply with some constants?
Is the magnetic momento of a proton = 0?
 
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You would need such a huge external field to make the two proton spin orientations differ in energy by 150 keV.
+- some numerical prefactors maybe.
 
You are right, not only difficult for 2 hydrogens but almost impossible due heating over some eV they may get divorced :).

Single protons that have almost the same moment: 2.7928473508 but I suppose may be impossible align all ions due temperature makes them go free pointing anywere and the magnetic field is shielded by external ions and electrons.

I do not know about how is proton internal structure, but seems to be like a charged bump on surface rotating to create a loop that generates a magnetic dipole

Where mathematics prefactors can be found?, I have not bibliography of "atom spin and momentum" or a sample exercise about that and I have to include calculus in a small excel sheet that I am making
 
Javier Lopez said:
I do not know about how is proton internal structure, but seems to be like a charged bump on surface rotating to create a loop that generates a magnetic dipole
No, the magnetic moment is purely from spin of the proton.

Experimentally we cannot rule out a contribution from an electric dipole moment but it has to be tiny.
https://arxiv.org/abs/1502.04317
Javier Lopez said:
Where mathematics prefactors can be found?
If in doubt: In textbooks.
 
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