Magnetic Forces and Magnetic Field

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Homework Help Overview

The discussion revolves around a problem involving a charged particle moving in a magnetic field, specifically focusing on the time taken for the particle to complete one revolution. The subject area includes concepts from electromagnetism and circular motion.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants express uncertainty about how to relate time to magnetic formulas and the charge-to-mass ratio. Some attempt to derive relationships between force equations and circular motion, while others question the adequacy of the given data for calculating velocity.

Discussion Status

Some participants have provided insights into the relationships between magnetic force and centripetal force, suggesting rearrangements of formulas. However, there is no explicit consensus on the approach, and the discussion reflects a mix of confusion and attempts to clarify the problem.

Contextual Notes

One participant notes a lack of sufficient data to link time with the magnetic formulas, highlighting the challenge of working with the charge-to-mass ratio in this context.

aesura
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Homework Statement



A charged particle with a charge-to-mass ratio of |q| / m = 5.7x10^8 C/Kg travels on a circular path that is perpendicular to a magnetic field whose magnitude is 0.72 T.

How much time does it take for the particle to complete one revolution?

Homework Equations



errrr.. I have no clue where to start with

The Attempt at a Solution



:( :(

Thank you for your help...
 
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*bump*

i tried to work it tho...not like I am just posting a new thread HEY GUYS COULD U PLEASE DO THIS FOR ME??

the trouble I am having is that I can't link t with all my magnetic formulas... and I've never heard of charge mass ratio...

i tried to work out hte velocity but... not enough data for it...

anyway physicists we need you!
 
Fm=qvB
Fc=(mv2)/r
because the particle is moving on a circular path,
so Fm=Fc
rearrange the formula to q/m=?, then solve for the radius
then use the radius to find the circumference,
d/t=v
where d is the circumference
Hope that helps
 
Last edited:
hmmm yea :( indeed... damn it... sorry I am med student not a physicist...

that was easy... :*( :*(

F = q v b sin 90
F = qvb

F = mv^2 / r ... obviously since a = v^2/r since it is a centri. force...

qvb = mv^2/r
q/m = v^2/rB
5.7x10^8 C/Kg = v/rB since v must be 2pi... :(


5.7x10^8 C/Kg x r = 2pi/0.72T

r = 1.53 x10^8 s

thank you so much... this is the correct answer... thanks heaps :)
 

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