- #1
hunter457
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Homework Statement
A 1.84kg mass is observed to accelerate at 10.66m/s^2 in a direction 28.8 degrees north of east. There is a force directed north acting on the object and a force directed east acting on the object. What is the magnitude of the force acting east on the object?
Homework Equations
F=ma, Fx=ma, Fy=ma
The Attempt at a Solution
*FA=force directed north, FB=force directed east, FN=normal force
Fx=ma
-mgsinθ+FAcosα+FBsinβ=ma
-(1.84)(9.8)(sin28.8)+FA(cos61.2)+FB(sin61.2)=(1.84)(10.66)
-8.68698+0.48175FA+0.8763FB=19.6144
0.48175FA+0.8763FB=28.30138
FA=(28.30138-0.8763FB)/0.48175
Fy=ma
FN+FAsinα-FBcosβ-mgcosθ=ma
FN+FAsin61.2-FBcos61.2-(1.84)(9.8)(cos28.8)=(1.84)(10.66)
FN+0.8763FA-0.48175FB-15.8=19.6144
FN+0.8763FA-0.48175FB=35.416
FA=(35.416-FN+0.48175FB)/0.8763
If I put the two equations together to cancel out FA, I still have two unknowns. I don't know what I'm doing wrong. Maybe my FBD was wrong?