Markov Chain - Is state 2 periodic?

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SUMMARY

The Markov chain defined by the probability transition matrix $\begin{pmatrix} 0 & 1/3 & 2/3\\ 1/4 & 3/4 & 0\\ 2/5 & 0 & 3/5 \end{pmatrix}$ is irreducible, as all states communicate. State 2 is confirmed to be non-periodic due to the condition that $P_{2,2} \ne 0$, allowing returns to state 2 after any number of steps. Furthermore, since all states are aperiodic, the Markov chain is also ergodic.

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mathmari
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Hey! :o

Given the Markov chain $\{X_n, n \geq 1\}$ and the following probability transition matrix:
$\begin{pmatrix}
0 & 1/3 & 2/3\\
1/4 & 3/4 & 0\\
2/5 & 0 & 3/5
\end{pmatrix}$

All states communicate, so the chain is irreducible, isn't?

Could you tell me if the state $2$ is periodic?
 
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mathmari said:
Hey! :o

Given the Markov chain $\{X_n, n \geq 1\}$ and the following probability transition matrix:
$\begin{pmatrix}
0 & 1/3 & 2/3\\
1/4 & 3/4 & 0\\
2/5 & 0 & 3/5
\end{pmatrix}$

All states communicate, so the chain is irreducible, isn't?

Could you tell me if the state $2$ is periodic?

Yes, the chain is irreducible!... the fact that $P_{2,2} \ne 0$ makes possible the return in the state 2 after any number of steps so that the state 2 is non periodic. In fact none of the states of the TM is periodic... Kind regards $\chi$ $\sigma$
 
chisigma said:
Yes, the chain is irreducible!... the fact that $P_{2,2} \ne 0$ makes possible the return in the state 2 after any number of steps so that the state 2 is non periodic. In fact none of the states of the TM is periodic... Kind regards $\chi$ $\sigma$

Ok! And is the chain ergodic?
 
mathmari said:
Ok! And is the chain ergodic?

The MC has all aperiodic states so that it is ergodic...

Kind regards

$\chi$ $\sigma$
 
chisigma said:
The MC has all aperiodic states so that it is ergodic...

Kind regards

$\chi$ $\sigma$

Ok! Thank you for your answer! :o
 

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