Mass lost in a single fusion reaction

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Discussion Overview

The discussion centers on the mass lost during a deuterium and tritium (D + T) fusion reaction, specifically the conversion of mass to energy and the calculations involved in determining the mass defect. Participants explore the details of the reaction, including the products formed and the energy released.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant asks about the total mass lost in the D + T fusion reaction and whether all of it is converted to energy.
  • Another participant asserts that not all mass is converted to energy since a helium nucleus is produced, and corrects the reaction equation to include a neutron.
  • A participant expresses uncertainty about their calculation of mass lost, providing a specific value in kg and requesting confirmation.
  • Another participant provides a mass loss value in atomic mass units, suggesting a conversion for clarity.
  • A participant agrees with the previous correction and challenges the accuracy of another participant's numbers, recommending a resource for experimental values.
  • One participant explains the mass defect calculation and suggests checking for errors if results differ from expected values.

Areas of Agreement / Disagreement

Participants express differing views on the amount of mass lost and the interpretation of the mass-energy conversion in the fusion reaction. There is no consensus on the accuracy of specific calculations or values presented.

Contextual Notes

Participants reference specific values and calculations, but there are indications of potential errors or misunderstandings in the numerical results. The discussion does not resolve these discrepancies.

eXmag
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How much mass is lost in a single D + T= 4He fusion reaction? And is all of the mass lost converted to energy or just some? The mass lost can be converted to energy using e=mc2.
 
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Obviously, all of the mass is not converted to energy, since a helium nucleus is produced.

Your reaction equation is also slightly off:

D + T = 4He + n

The energy produced is 17.6 MeV, which is equivalent to about 18.9*10-3 atomic mass units.
 
I don't think you understand what I am asking. I am getting roughly around 4.7x10^-29 kg mass lost but I wanted to confirm this. You can convert that to atomic mass units if you wish but I prefer in kg. Thanks
 
which is about 0.0283u of mass lost
 
m(D) + m(T) - m(4He) - m(n) = mass defect and it will be equal to energy produced in the reaction. If you are getting something different, check for errors.
 

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