Mass of silver to cover a 2.0 x10^2 cm2 object with .20mm thick layer

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SUMMARY

To determine the mass of silver required to coat an object with a surface area of 2.0 x 102 cm2 and a thickness of 0.20 mm, first calculate the volume of silver needed using the formula for volume (V = surface area x thickness). The volume is then converted to mass using the density of silver, which is 10.49 g/cm3. The final mass of silver required is 4.196 grams.

PREREQUISITES
  • Understanding of volume calculation (V = surface area x thickness)
  • Knowledge of density and its application (d = m/v)
  • Familiarity with unit conversions (mm to cm)
  • Basic algebra for solving equations
NEXT STEPS
  • Learn about unit conversions, specifically converting millimeters to centimeters.
  • Study the properties of density and how to apply them in calculations.
  • Explore volume calculations for different geometric shapes.
  • Review algebraic manipulation techniques for solving equations.
USEFUL FOR

Students in physics or chemistry courses, educators teaching material properties, and anyone involved in materials science or engineering applications.

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Homework Statement



if an object to be coated in a .20mm thick layer with a surface area of 2.0x10^2 cm^2, what is the mass of the silver required? (density of silver is 10.49 g/cm^3)

Homework Equations



d=m/v , surface area formula? not sure which one


The Attempt at a Solution



i know i am to use the surface area and depth info to calculate the volume of silver required to plate the object, then use the density provided to convert it to grams..

but not sure where to start..
 
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geoti8 said:

The Attempt at a Solution



i know i am to use the surface area and depth info to calculate the volume of silver required to plate the object, then use the density provided to convert it to grams..

but not sure where to start..

Start where you said: use the surface area and depth info to calculate the volume.
 

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