Material/Fluid derivative operator questions

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    Derivative Operator
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SUMMARY

The discussion centers on the material derivative operator, specifically its derivation and application in fluid dynamics. The material derivative, denoted as \(\frac{Df}{Dt}\), is derived using the chain rule and accounts for both spatial and temporal variations of a property, such as density, represented as \(f(\rho) = f(x,y,z,t)\). The operator incorporates the velocity field of the fluid, denoted by \(u\), \(v\), and \(w\), and is essential for analyzing properties that follow a fluid parcel's movement. The equation \(\frac{Df}{Dt} = \frac{\partial f}{\partial t} + (u \cdot \nabla)f\) encapsulates this relationship.

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  • Understanding of fluid dynamics concepts, particularly the material derivative.
  • Familiarity with vector calculus, including gradient and divergence operations.
  • Knowledge of partial derivatives and their significance in multivariable functions.
  • Basic grasp of the chain rule in calculus.
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The above link shows the material derivative. Which is the derivative that follows a volume of fluid throughout its movement through a fluid. How is this derived from a chain rule? Is the v in that equation the velocity field of the fluid at each point throughout space? Do you act on the position of some arbitrary fluid volume with this operator? Thanks ahead of time.
 
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Suppose you have a property of interest, say density.

This property varies in both space and time so f(ρ) = f(x,y,z,t).

We have to consider what we mean by the partial time derivative \frac{{\partial f}}{{\partial t}}

This means the time variation of ρ at a fixed point in space (x,y,z t) since we hold x,y,z constant to take the partial derivative with respect to t.

If we want toconsider 'following' a parcel of fluid then we use the rate of change 'following the fluid' \frac{{Df}}{{Dt}}

This is derived as follows.


\frac{{Df}}{{Dt}} = \frac{{\partial f}}{{\partial x}}\frac{{dx}}{{dt}} + \frac{{\partial f}}{{\partial y}}\frac{{dy}}{{dt}} + \frac{{\partial f}}{{\partial z}}\frac{{dz}}{{dt}} + \frac{{\partial f}}{{\partial t}} = \frac{{\partial f}}{{\partial t}} + u\frac{{\partial f}}{{\partial x}} + v\frac{{\partial f}}{{\partial y}} + w\frac{{\partial f}}{{\partial z}} = \frac{{\partial f}}{{\partial t}} + (u.\nabla )f

Does this help?
 
Studiot said:
Suppose you have a property of interest, say density.

This property varies in both space and time so f(ρ) = f(x,y,z,t).

We have to consider what we mean by the partial time derivative \frac{{\partial f}}{{\partial t}}

This means the time variation of ρ at a fixed point in space (x,y,z t) since we hold x,y,z constant to take the partial derivative with respect to t.

If we want toconsider 'following' a parcel of fluid then we use the rate of change 'following the fluid' \frac{{Df}}{{Dt}}

This is derived as follows.


\frac{{Df}}{{Dt}} = \frac{{\partial f}}{{\partial x}}\frac{{dx}}{{dt}} + \frac{{\partial f}}{{\partial y}}\frac{{dy}}{{dt}} + \frac{{\partial f}}{{\partial z}}\frac{{dz}}{{dt}} + \frac{{\partial f}}{{\partial t}} = \frac{{\partial f}}{{\partial t}} + u\frac{{\partial f}}{{\partial x}} + v\frac{{\partial f}}{{\partial y}} + w\frac{{\partial f}}{{\partial z}} = \frac{{\partial f}}{{\partial t}} + (u.\nabla )f

Does this help?

Thanks for the response. So you are saying that some function of a specific property we are interested in is a function of (x,y,z,t). "f(ρ) = f(x,y,z,t)". I would say that ρ=f(x,y,z,t), but I guess it is more general to state it as you did. Is this correct?
 

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