MHB Math Game HELP: Solve Hard Task with Invariants

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The discussion revolves around a mathematical game involving a positive whole number that is transformed based on its parity. If the number is even, it is halved; if odd, one can choose between two transformations, \(3n-1\) or \(3n+1\). The connection to the unsolved Collatz conjecture is highlighted, with a specific variation allowing for the choice between the two transformations. A key insight is that selecting the transformation that results in a multiple of 4 leads to a sequence of steps that reduces the number, ultimately suggesting that reaching 1 is possible. The conversation emphasizes the importance of strategic choice in the transformations to ensure a decrease in value.
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HELP - math game

A positive whole number was written on the board. In each step we rub out the number $$n$$ (written on the board) and we write a new one. If number $$n$$ is even, then we write number $$\frac{n}{2}$$ on the board. If number $$n$$ is odd, then we choose one of the numbers: $$3n-1$$ or $$3n+1$$ and we write it down on the board. Decide, if after finite amount of steps, we can obtain the number 1 one the board (no matter which number was written on the board at the beginning).

Please help. I can't figure it out. I know that it can be connected to invariants.
 
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Deveno said:
This is the Collatz conjecture. It is currently unsolved.

Yes, I found it but there is one extra variation. You can choose either $$3n+1$$ or $$3n-1$$. Doesn't it have an influence on the result?
 
If at some stage of the game you have an odd number $n$ then one of the numbers $3n\pm1$ will be a multiple of $4$. Choose that one. Then the next two steps will take you to the number $\dfrac{3n\pm1}4$, which is strictly smaller than $n$. This process of making numbers strictly smaller will inevitably bring you down to $1$ eventually.
 
There is a nice little variation of the problem. The host says, after you have chosen the door, that you can change your guess, but to sweeten the deal, he says you can choose the two other doors, if you wish. This proposition is a no brainer, however before you are quick enough to accept it, the host opens one of the two doors and it is empty. In this version you really want to change your pick, but at the same time ask yourself is the host impartial and does that change anything. The host...

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