Math Game HELP: Solve Hard Task with Invariants

  • Context: MHB 
  • Thread starter Thread starter Mathick
  • Start date Start date
  • Tags Tags
    Game Hard
Click For Summary
SUMMARY

The discussion centers on a mathematical game related to the Collatz conjecture, specifically exploring the process of transforming a positive whole number through defined operations. When the number \( n \) is even, it is halved, while if it is odd, one can choose between \( 3n-1 \) or \( 3n+1 \). The key insight shared is that selecting the option that results in a multiple of 4 leads to a sequence of operations that ultimately reduces the number to 1. This variation of the conjecture suggests a definitive pathway to the solution.

PREREQUISITES
  • Understanding of the Collatz conjecture
  • Basic knowledge of mathematical invariants
  • Familiarity with even and odd number properties
  • Concept of sequences and limits in mathematics
NEXT STEPS
  • Research the implications of the Collatz conjecture variations
  • Study mathematical invariants and their applications in number theory
  • Explore the properties of sequences in mathematics
  • Investigate existing proofs or attempts related to the Collatz conjecture
USEFUL FOR

Mathematicians, students of number theory, and anyone interested in unsolved mathematical problems and conjectures.

Mathick
Messages
23
Reaction score
0
HELP - math game

A positive whole number was written on the board. In each step we rub out the number $$n$$ (written on the board) and we write a new one. If number $$n$$ is even, then we write number $$\frac{n}{2}$$ on the board. If number $$n$$ is odd, then we choose one of the numbers: $$3n-1$$ or $$3n+1$$ and we write it down on the board. Decide, if after finite amount of steps, we can obtain the number 1 one the board (no matter which number was written on the board at the beginning).

Please help. I can't figure it out. I know that it can be connected to invariants.
 
Last edited:
Physics news on Phys.org
Deveno said:
This is the Collatz conjecture. It is currently unsolved.

Yes, I found it but there is one extra variation. You can choose either $$3n+1$$ or $$3n-1$$. Doesn't it have an influence on the result?
 
If at some stage of the game you have an odd number $n$ then one of the numbers $3n\pm1$ will be a multiple of $4$. Choose that one. Then the next two steps will take you to the number $\dfrac{3n\pm1}4$, which is strictly smaller than $n$. This process of making numbers strictly smaller will inevitably bring you down to $1$ eventually.
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 25 ·
Replies
25
Views
5K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K