How would you solve the following system of simultaneous equations for t and b?(adsbygoogle = window.adsbygoogle || []).push({});

sin(pi*t) = 0

sin(pi*(t^2 + 35)/(2*t)) = 0

(t^2 + 35)/(2*t) - t/2 - b/2 = 0

t^2/35 +35/t^2 -t/b - b/t = 0

t*b = 35

inquisitively,

Edwin G. Schasteen

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# Math Question

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