Mathematica Representation of a wave

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SUMMARY

The discussion focuses on solving a physics problem related to wave propagation along a stretched string, specifically using the mathematical representation of a wave given by the equation y(x, t) = A cos(2π (x/λ - t/T)). The user correctly identified the period as 0.04 seconds and the amplitude as 4 mm. However, they initially miscalculated the wavelength, arriving at an incorrect value of 0.78 m instead of the correct 0.14 m. The solution involves understanding the relationship between distance traveled by the wave and the time taken, emphasizing the importance of analyzing the wave's characteristics.

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Homework Statement



"A sinusoidal wave is propagating along a stretched stringas a function of time is graphed in the figure (attached) for particles at x = 0 and x =0.0900m. a) what is the period of the wave ( my ans = 0.04 sec

b) what is the amplitude of the wave ( my ans = 4mm)

c)you are told that the 2 points x=0 and x=0.0900m are within one wavelength of each other. If the wave is moving in the +x direction, determine the wavelength and the wave speed."





Homework Equations



y(x ,t) = A cos(2pi ( x/lambda - t/T))

ie the mathematical representation of a wave

The Attempt at a Solution



I have already posted this Q previously, but fear that how I posted it made it seem unsolvable, this is what I did again:

0.75 = cos (2pi (0.09/lambda - 0 )) where I get lambda, and thus wavelength to equal 0.78... which isn't correct since the answer is something like 0.14m

any pointers on how to solve would be great!
 

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    wave figure.jpg
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I can't open your attachment as yet (its still pending approval) but I'll assume you took the period and amplitude from information of the graphs.

Do the two graphs should show a phase difference? If they do, you can easily use this to establish how long the wave takes to get from the first point to the second. Youve then got a distance and a time from which a speed is easy.
 
yeah i got it now...u use the distance travelled...ie between 2 waves...so from say a peak to the next peak ...adn diide by time...makes it REAL simple when you consider this way...cheers for the attempt...no1 else seemed to b able to get it?
 

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