Mathematical induction w/ Summation question

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Homework Help Overview

The discussion revolves around a mathematical induction problem involving the summation of the expression i(i + 1) from i = 2 to n - 1, with the goal of proving a specific formula for all integers n ≥ 2.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to establish the base case P(2) and subsequent cases P(k) and P(k+1) but expresses confusion over the correctness of their approach. Some participants question the validity of the initial formula and suggest clarifying the lower limit of the summation.

Discussion Status

Participants are actively engaging in clarifying the induction process and the conditions under which the summation is defined. Guidance has been offered regarding the correct interpretation of the problem and the necessary steps for induction, though there is no explicit consensus on the correctness of the original poster's formulation.

Contextual Notes

There is mention of a potential typo in the original problem statement, indicating that the summation might need to start from i = 1 instead of i = 2 for the formula to hold true. This raises questions about the assumptions made in the problem setup.

Jim01
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Homework Statement



Summation of i(i + 1) (with i going from i = 2 to i = n-1) = n(n-1)(n=1) / 3

a. Write P(2). Is P(2) true?

b. Write P(k)

c. Write P(k+1)

d. Prove by mathematical induction that the formula holds true for all integers
n [tex]\geq[/tex] 2



Homework Equations



N/A

The Attempt at a Solution



a. P(2): i(i+ 1) + ... + (n-1)[(n-1)+1] = n(n-1)(n+1) / 3

= (2-1)[(2-1) + 1] = 2(2-1)(2 + 1) / 3

P(2): 2 = 2

P(2) is true

b. P(k): ...+ (k-1)[(k-1)+1] = k(k-1)(k+1) / 3

P(k) = k(k-1) = k(k2 - 1)/3

c. P(k+1): (k+1)(k-1) = (k+1)[(k+1)2 - 1) / 3
= k2 - 1 = k3 + 3k2 + 2k / 3

d. Left-Hand side of P(k+1) = i(i + 1) + ... + (k+1)(k-1)
= i(i + 1) + ... + k(k-1) + (k+1)(k-1)
= k(k2 - 1)/3 + 3k2 -3 / 3
= 4k2 - 4


Right-Hand side of P(k+1) = k3 + 3k2 + 2k / 3

4k2 - 4 = k3 + 3k2 + 2k / 3


I've went over this several times and it doesn't work out so I am obviously doing something
wrong, but I am not sure where I am making the mistake.
 
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You are doing induction wrongly; perhaps you do not understand what is involved. To clarify: let S(n) = sum{i*(i+1): i=2..n-1} and let P(n) = n*(n-1)*(n+1)/3. You are being asked to prove that S(n) = P(n) for all n >= 3. To show it by induction, you must establish that S(3) = P(3) (n = 3 is the smallest integer for which the summation S(n) makes sense---unless the lower limit is i = 1 instead of i = 2). Anyway, having established that S(3) = P(3) and *assuming that* S(k) = P(k) (for some k >= 3), then you must prove that S(k+1) = P(k+1) also holds. That will prove that S(n) = P(n) holds for all n >= 3.

R.G. Vickson
 
Ray Vickson said:
You are doing induction wrongly; perhaps you do not understand what is involved. To clarify: let S(n) = sum{i*(i+1): i=2..n-1} and let P(n) = n*(n-1)*(n+1)/3. You are being asked to prove that S(n) = P(n) for all n >= 3. To show it by induction, you must establish that S(3) = P(3) (n = 3 is the smallest integer for which the summation S(n) makes sense---unless the lower limit is i = 1 instead of i = 2). Anyway, having established that S(3) = P(3) and *assuming that* S(k) = P(k) (for some k >= 3), then you must prove that S(k+1) = P(k+1) also holds. That will prove that S(n) = P(n) holds for all n >= 3.

R.G. Vickson

Thank you Mr. Vickson. You are right, I don't understand. I thought I was following the example in the book step-by-step. I will go back and reread that section. The book only gives one example, so I will take a look around the Internet and see if I can't find more examples that may shed more light on the subject.

Thank you for your help and guidance.
 
Jim01 said:
Thank you Mr. Vickson. You are right, I don't understand. I thought I was following the example in the book step-by-step. I will go back and reread that section. The book only gives one example, so I will take a look around the Internet and see if I can't find more examples that may shed more light on the subject.

Thank you for your help and guidance.
One problem is that you are being asked to prove an incorrect result (or else you made a typo when you wrote out the question). Try proving that
sum{i*(i+1), i=1..n-1} = n*(n-1)*(n+1)/3 for n >= 2.

RGV
 

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