Mathematically Explain Non-defined Status of s=1

  • Context: Undergrad 
  • Thread starter Thread starter electronic engineer
  • Start date Start date
Click For Summary
SUMMARY

The discussion centers on the mathematical implications of the equation s=1+(y/x) when both x and y approach zero. It is established that while s is often said to equal 1 when both x and y are zero, this is mathematically incorrect as y/x is undefined in that scenario. The limits of s vary based on the path taken towards (0,0); for instance, approaching along y=x yields a limit of 2, while y=-x results in a limit of 0. This highlights the importance of path dependence in limit calculations in calculus.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with undefined expressions in mathematics
  • Knowledge of mathematical notation and functions
  • Basic concepts of continuity and differentiability
NEXT STEPS
  • Study the concept of limits in multivariable calculus
  • Learn about path-dependent limits and their implications
  • Explore the definition and properties of undefined expressions
  • Investigate the continuity of functions in different dimensions
USEFUL FOR

Mathematics students, educators, and anyone interested in advanced calculus concepts, particularly those dealing with limits and undefined expressions.

electronic engineer
Messages
145
Reaction score
3
let's assume such equation:

s=1+(y/x)

we usually say that s=1 when both x,y has Zero value

how to explain that mathematically?!
 
Mathematics news on Phys.org
no, we can't say x and y are 0, but we must stipulte y/x = 0. If y and x both = zero, then the value s is undefined since y/x is undefined. And if y/x = 0, then y=0, and x is not equal to 0.
 
electronic engineer said:
let's assume such equation:

s=1+(y/x)

we usually say that s=1 when both x,y has Zero value

how to explain that mathematically?!

I can't explain it because I would never say such a thing! If you approach (0,0) along the line y= x, then s will have a limit of 2. If you approach along the line y= -x, then s will have limit of 0. In fact, given any value a, then approaching (0,0) along the line y= (a-1)x, s has limit a.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
950
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 13 ·
Replies
13
Views
3K