MATLAB [MATLAB] Simple Undamped Forced Vibration Problem

  • Thread starter Thread starter bugatti79
  • Start date Start date
  • Tags Tags
    Matlab Vibration
Click For Summary
The discussion centers on replicating a solution in MATLAB for a second-order linear differential equation using two first-order equations. The user provides their MATLAB code, which utilizes the `ode45` function to solve the system and plot displacement versus time. They express uncertainty about whether MATLAB considers both the complementary and particular solutions in its output. The theoretical solution is presented, highlighting the need for the particular solution derived from boundary conditions. A suggestion is made to verify the output of `ode45` by comparing it against the theoretical form through plotting, emphasizing the importance of checking if the particular solution is correctly implemented in MATLAB.
bugatti79
Messages
786
Reaction score
4
Hi Folks,

I am trying to replicate a solution in Matlab for the following problem ##\displaystyle \ddot x + \frac{k}{m}x = \frac{F_o}{m} \sin w_ot##

using 2 first order linear differential equations in Matlab as shown below


tspan=[0 4];
y0=[.02;1]; %Initial Conditions for y(1)=x and y(2)= x dot
[t,y]=ode45(@forced1,tspan,y0); %Calls forced1.m
plot(t,y(:,2)); %y(:,1) represents the displacement and y(:,2) the velocity
grid on
xlabel('time')
ylabel('Displacement')
title('Displacement Vs Time')
hold on;

function yp = forced1(t,y)

m=20;
k=800;
f=8;
w=8;
yp = [y(2);(((f/m)*sin(w*t))-((k/m)*y(1)))];

The problem is I don't know whether Matlab considers both the complementary and particular solution. THe theoretical solution is given as

##\displaystyle x=A \sin w_nt +B \cos w_nt+ \frac{\frac{F_o}{k}}{1-(\frac{w_o}{w_n})^2} \sin w_ot##

where the 3rd term is the particular solution assumed of the form ##x_p=C \sin w_o t##. I am not sure how to implement this correctly in Matlab

Any ideas?

Thanks
 
Physics news on Phys.org
Have you confirmed that MATLAB isn't giving you this answer back? It should be easy to check the output of ode45 against that form with a few plots.

Does that particular solution arise as a result of boundary conditions?
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 6 ·
Replies
6
Views
4K