Max Dist Compressed: .99m - Find Out How With Vibrations & Waves

[physics_ash82]

A 500-g block is released from rest and slides down a frictionless track that begins 2.00 m above the horizontal as shown in the figure. At the bottom of the track, where the surface is horizontal, the block strikes and sticks to a light spring with a constant of 20 N/m.find the maximum distance the spring is compressed.

I think that I use the formula mgh=1/2kx^2 is this right?

so when i use this i get (.500)(9.8)(2)=.5(20)(x^2)

and solving for x i get .99m is this right?

 

[andrewchang]

i don't get how this has to do with vibration and waves.

but yes, that seems correct

 

[physics_ash82]

well that is what chapter it is in sry I didn't really know what to put in heading. Thanks though
ash