Undergrad Does Continuity of F Affect the Maximal Solution Theorem?

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The discussion centers on the implications of continuity versus local Lipschitz conditions for the maximal solution theorem in differential equations. It highlights that if the function F is continuous and locally Lipschitz, the maximum solution diverges as the upper limit of the interval approaches infinity. The question posed is whether similar results hold if F is only continuous, suggesting a need for clarification on the uniqueness of solutions under these conditions. Participants note that the local Lipschitz condition is essential for ensuring the uniqueness of local solutions. The conversation emphasizes the importance of these mathematical properties in understanding the behavior of solutions to differential equations.
Calabi
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Hello, I know a theorem that say that if ##F : \mathbb{R} \times \Omega \rightarrow E## is continuous and local lispchitziann in is seconde set value(where ##\Omega## is an open of a Banach space E.). we have that the maximum solution ##(\phi, J)##(where J is an open intervall and ##\phi : J \rightarrow \Omega## is ##C^{1}## .). of ##\phi'(t) = F(t, \phi(t))## diverge if ##sup(J) < + \infty##(##lim_{t \rightarrow sup(J)} \phi(t) = +\infty##.).

Is there the same results if F is just continuos please?

Thank you in advance and have a nice aftrenoon:oldbiggrin:.
 
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Hello and thanks. In fact I recently knew that the local lipschitz condition is necessar for the uniqueness of a local solution to a diffential equation. I can give more if you want.
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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