Maximum Yield of Ca(OH)2 from Ca and H2O

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SUMMARY

The maximum yield of calcium hydroxide (Ca(OH)2) from the reaction of calcium (Ca) and water (H2O) is determined by identifying the limiting reactant. In this case, 11.27 g of Ca and 17.8 g of H2O are used. The process involves calculating the number of moles of each reactant and determining which one produces the lesser amount of Ca(OH)2, thereby establishing the maximum yield. The final answer corresponds to the limiting reagent, which is the reactant that produces the lower yield of the product.

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  • Stoichiometry of chemical reactions
  • Mole calculations for reactants
  • Understanding of limiting reactants
  • Basic knowledge of chemical equations
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For the reaction

Ca + 2 H2O → Ca(OH)2 + H2

what is the maximum amount of Ca(OH)2
which could be formed from 11.27 g of Ca and
17.8 g of H2O?
Answer in units of g


Would I use the limiting reactant type of format to solve this problem? Like find how much Ca would produce Ca(OH)2 and how much H2O would produce Ca(OH)2 and then my final answer would be my the answer that has the greater value? Is that right? Or am I on the wrong track?
 
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Yes, you will have to find the limiting reagent. Start by finding the number of moles of the reactants.
 
dumbasian said:
Like find how much Ca would produce Ca(OH)2 and how much H2O would produce Ca(OH)2 and then my final answer would be my the answer that has the greater value?

Like the final answer would be the one with the LOWER value.
 

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