Mean and standard deviation problem

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SUMMARY

The mean and standard deviation of a random variable X are given as -11 and 4, respectively. For the transformed random variables, the mean and standard deviation can be calculated using the equations E(Y) = E(X) + 7 and E(V) = 8E(X). The standard deviation for V is determined by the formula SD(V) = 8 * SD(X), resulting in a standard deviation of 32. The variance of a transformed random variable is calculated using Var(Y) = a²Var(X), where a is a constant multiplier.

PREREQUISITES
  • Understanding of random variables and their transformations
  • Familiarity with the concepts of mean (expectation) and standard deviation
  • Knowledge of variance and its relationship to standard deviation
  • Basic mathematical statistics, particularly theorems related to random variables
NEXT STEPS
  • Study the properties of expectation and variance in random variable transformations
  • Learn about the Central Limit Theorem and its implications for mean and standard deviation
  • Explore mathematical statistics textbooks for deeper insights into variance and standard deviation calculations
  • Practice problems involving the transformation of random variables using E(X) and Var(X)
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Students in statistics, data analysts, and anyone studying probability theory or mathematical statistics who seeks to understand the implications of transforming random variables.

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The mean and standard deviation of a random variable x are -11 and 4 respectively. Find the mean and standard deviation of the given random variables:

1) y=x+7

2) v=8x

3) w=8x+7




2. Homework Equations : E(x) = u, E(ax+b) = aE(x)+b



The Attempt at a Solution



I've gotten the standard deviations for these problems, though I'm still not sure why they are what they are. I can't figure out how to find the mean though. Can somebody please explain all of this to me? thanks.
 
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If you know E(X) = -11, what do your relevant equaitons tell you about E(X + 7)?
 
LCKurtz said:
If you know E(X) = -11, what do your relevant equaitons tell you about E(X + 7)?

- I get it. Can you explain the standard deviation portion for me? for instance, when v=8x, the standard deviation is 8*4, but I'm not sure why. Is x the standard deviation in the equation?
 
When you're dealing with the mean of a transformed random variable X, you can use expectation, E(...), to find the mean of the transformed variable. When you're dealing with the standard deviation, you need something else, Var(...), or variance of a random variable. As you probably know, the variance is the square of the standard deviation, or equivalently, the standard deviation is the square root of the variance.

Since you are asked about the mean and standard deviation of a transformed r.v., I'm going to assume you have been exposed to this concept.

In my book on mathematical statistics, there is a theorem that says:
Let X be a random variable and let a and b be constants. Define Y = aX + b. Then
Var(Y) = a2Var(X)​

Elsewhere in my text Var(X) is defined as E( (X - mu)2 ), which turns out to be equal to E(X2) - mu2.

In the problem, V = 8X, what would be Var(V)? Further, what would be the standard deviation of V?
 

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