High School Meaning of the word 'instantaneous'

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The discussion revolves around the meaning of "instantaneous" in the context of an electron emitting a photon, questioning whether it implies no time lag or a very small time lag. Participants express skepticism about the term's precision, emphasizing that quantum mechanics does not support the notion of instantaneous events without observable intermediate states. The conversation highlights the challenges of interpreting quantum phenomena using natural language, as well as the limitations imposed by the uncertainty principle on measuring emission times. Additionally, the debate touches on the implications of entanglement and the nature of information transfer in quantum mechanics, suggesting that the term "instantaneous" may not be rigorously definable. Overall, the discussion underscores the complexity of accurately describing quantum processes.
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" an electron emits a photon instantaneously" or consider other instantaneous reactions.

What is meant by instantaneous here?

Does it mean there is no time lag between the emission? Does it mean that the emission takes place at a speed greater than the speed of light?
 
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I've no clue. Of course, in nature nothing happens instantaneously, and a photon needs a (however very short time) to form. Where does this statement come from? I hope, it's not from a serious textbook but from a popular-science book. Note that there are almost no good popular-science books on physics. There are some exceptions: Feynman's books like QED, Weinberg, The first three minutes, Ledermann and Teresi, The God Particle.
 
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Deepak K Kapur said:
Does it mean there is no time lag between the emission? Does it mean that the emission takes place at a speed greater than the speed of light?
Questions like this are why we have to be cautious about natural language descriptions of phenomena that are more precisely described mathematically - words like "instantaneous" may not be as precise as the speaker had hoped.

You haven't provided the source of the quotation so we have no context and can only guess at what was intended. However, there's a fair chance that they were trying to say that we start in a state with no photon and end up in a state with a photon - but that there are no observable in-between states in which the photon is only partly emitted.
 
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Nugatory said:
Questions like this are why we have to be cautious about natural language descriptions of phenomena that are more precisely described mathematically - words like "instantaneous" may not be as precise as the speaker had hoped.

You haven't provided the source of the quotation so we have no context and can only guess at what was intended. However, there's a fair chance that they were trying to say that we start in a state with no photon and end up in a state with a photon - but that there are no observable in-between states in which the photon is only partly emitted.
This is from a debate/discussion on the nature of reality on you tube in which 9-10 scientists participated.

The actual point is 'is there really no time lag when an electron emits a photon.'
 
I think people are not viewing this thread (especially the expert ones)

OK. I ask in a different way.

What does instantaneous mean?

1. No time lag.

2. A very-very-very small time lag.

This would be easy, hopefully...
 
Again, experts are not too interested in pseudo-science. You also have not given your source, where this at best inaccurate statement comes from. It starts with the fact that for itself a single electron cannot emit a photon. You either need it to scatter, leading to bremsstrahlung, or it's bound in an atom and changes from an excited energy level within the atom to a lower-lying energy level (either by stimulated or spontaneous emission).

As I already stated according to quantum theory there is no instanteneous and also no jumps. However, within the here applicable quantum field theory, it is impossible to interpret the transient states during the time evolution where interactions are relevant, in a particle-like fashion. All that's possible to calculate from QFT (in this case QED) are S-matrix elements, which describe the transition-probability rates from an asymptotic free initial (here an electron plus some other particle it scatters from or an electron bound within an atom) to another asymptotic free final state (here an electron + other particles + a photon, or an electron bound in another lower-energy atomic state + a photon).
 
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vanhees71 said:
according to quantum theory there is no instanteneous .

What about EPR?
 
By construction of relativistic QFT there are no instantaneous interactions at a distance either. This has been discussed countless times in this forum.
 
vanhees71 said:
By construction of relativistic QFT there are no instantaneous interactions at a distance either. This has been discussed countless times in this forum.
You seem to have made a sweeping statement. EPR is considered to be an instantaneous phenomenon(not interaction).
 
  • #10
ftr said:
EPR is considered to be an instantaneous phenomenon(not interaction).
One could construct a classical version of EPR using two counter rotating gyroscopes. A small explosive device separates the two. Sometime later you measure one gyroscope and, as if by magic, in an instant, you predict the direction of the unmeasured one. Clearly, no non-local interaction is needed to account for this astounding fact. What sticks in peoples craw is the quantum nature of the observables not the correlation.

Now, in regard to the photon emission, how exactly is the time of emission to be known?
 
  • #11
Paul Colby said:
One could construct a classical version of EPR using two counter rotating gyroscopes. A small explosive device separates the two. Sometime later you measure one gyroscope and, as if by magic, in an instant, you predict the direction of the unmeasured one. Clearly, no non-local interaction is needed to account for this astounding fact. What sticks in peoples craw is the quantum nature of the observables not the correlation.

Now, in regard to the photon emission, how exactly is the time of emission to be known?
The explanation you allude to is not a universal one(a minority). As for emission, that is exactly the point, the formalism imply it is instantaneous.
 
  • #12
ftr said:
As for emission, that is exactly the point, the formalism imply it is instantaneous.
Which formalism is that? Last I checked the formalism provides one with an absorption or detection rate. How is this a statement about emission time?
 
  • #13
Because there is no statement, that implies it is instantaneous.
 
  • #14
Moreover, I don't know why you find it strange since with superposition an electron has undefined state before measurement. That is even more stronger than "instantaneous".
 
  • #15
ftr said:
Because there is no statement, that implies it is instantaneous.
Not following your logic here. My point, in the limit one finds this interesting, is how exactly is one to frame this question from an experimental or observational point of view? It's unclear to me one may even define the emission time for an individual decay.
 
  • #16
The emission did happen, right?
 
  • #17
ftr said:
The emission did happen, right?
One may measure with a finite accuracy or time interval a time of detection. One may then infer again with some finite time interval the emission time based on the distance to the emitter. Neither of these may be confused with instantaneous. Nor do either of these numbers relate directly to the time it took to emit. For this one needs the time of excitation. How do you propose to determine that, and to what accuracy?
 
  • #18
The first quantization of interaction of light and matter does not go into mechanism. I think we are going in a circle.
 
  • #19
ftr said:
I think we are going in a circle.
I was trained as an experimentalist. If you think this is a circle that's likely because you frame questions based on an incomplete view of the theory. What is or is not an observable is a non-trivial question. Not everything in field theory is observable. For example the "blue" component of the quark field can't be observed directly because this would violate color symmetry. So, are you asking a question about something that is in principle observable? Framing even an idealized experiment helps give one insight into this type of question.

ftr said:
The first quantization of interaction of light and matter does not go into mechanism.
Okay, so what does the second quantization treatment tell us? Why limit your discussion to a theory known to be incomplete.
 
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  • #21
Well, "almost instantaneous" is not very quantitative. Can't say I'm interested enough to pay for the article. Things to remember, typical optical frequencies are many order of magnitudes above those encountered in electronics, though this gap is closing. The switching speeds of an optoelectronic device are likely larger than the absorption and emission times. These are still not zero.
 
  • #22
ftr said:
The first quantization of interaction of light and matter does not go into mechanism. I think we are going in a circle.
You cannot describe the emission of photons in first quantization. It's a typical "creation process", which is described by QFT or "2nd quantization" although 1st and 2nd quantization are misnomers, because there's one and only one quantum theory (in this case of electromagnetically interacting particles and radiation, i.e., QED).
 
  • #23
ftr said:
You seem to have made a sweeping statement. EPR is considered to be an instantaneous phenomenon(not interaction).
May be it is considered as such, but there's nothing instantaneous about it, at least not in the minimal statistical interpretation of QT (which is one of the strongest reason for me to consider this interpretation as the only consistent one known so far).
 
  • #24
I think they might have used instantaneous because the time in which the phenomena happened was too small to measure experimentally.
 
  • #25
Deepak K Kapur said:
I think people are not viewing this thread (especially the expert ones)

OK. I ask in a different way.

What does instantaneous mean?

1. No time lag.

2. A very-very-very small time lag.

This would be easy, hopefully...

Ha, fat chance. In the quantum and relativistic worlds, these can be interpreted in many ways. You really have to specify an exact context and then ask a question about that. Certainly experimental constraints, including the uncertainty principle, are issues. You have the notion of simultaneity as well. When someone says instantaneous, there is no expected time lag but there may be no way to really verify that. Many times the word "instantaneous" is used without necessarily imply that can be demonstrated rigorously.
 
  • #26
Deepak K Kapur said:
" an electron emits a photon instantaneously" or consider other instantaneous reactions.

What is meant by instantaneous here?

Does it mean there is no time lag between the emission? Does it mean that the emission takes place at a speed greater than the speed of light?
It's not clear what 'instantaneous' means. The uncertainty principle limits how well we can know when a photon is emitted.
 
  • #27
Can you give the link of the video. Maybe instantaneous in the sense that the speed is immediately c?
 
  • #28
Deepak K Kapur said:
" an electron emits a photon instantaneously" or consider other instantaneous reactions.

What is meant by instantaneous here?

Does it mean there is no time lag between the emission? Does it mean that the emission takes place at a speed greater than the speed of light?

Despite experimental verifications of Special Relativity, which requires non-simultaneity, contemporary quantum mechanical interpretations of entanglement depend upon instantaneous transfer of information. Contemporary physics has no self-consistent model for time.
 
  • #29
Android Neox said:
contemporary quantum mechanical interpretations of entanglement depend upon instantaneous transfer of information.
I know we go round and round on this, but, this statement isn't correct is it? Consider two Gyroscopes which are counter rotating which are separated using a torque free explosive device. These spins are correlated and require no information transfer and the situation is perfectly understandable. The problem arrises when the Gyroscopes are replaced with quantum ones. The very same experimental situation occurs in QM except the information is quantum mechanical, not classical. So, while we can think of each gyroscope carrying it's very own pointing direction we are forced by QM to consider each spin as carrying it's own state vector.
 
  • #30
Paul Colby said:
... we are forced by QM to consider each spin as carrying it's own state vector.

Clearly, an entangled system is one system (at least on the entangled basis) - so there is really no "separate state" vector in that sense.

Without a useful mechanical model to discuss, it is difficult to agree with Android's statement: "contemporary quantum mechanical interpretations of entanglement depend upon instantaneous transfer of information." If there is information being transferred, where is it going from/to? No contemporary interpretation seems to answer this in a satisfactory manner. (Even as the underlying formalism works.)
 

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