Measuring the energy of particles

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SUMMARY

Measuring the energy of relativistic particles in a beam is directly related to their momentum. The energy can be calculated using the equation \(E=c \sqrt{m^2 c^2+p^2}\), where \(m\) is the invariant mass and \(p\) is the three-momentum. For highly relativistic particles, the energy approximates the momentum, allowing for practical calculations in scenarios such as those encountered in the LHCb detector. Accurate energy measurements require knowledge of the particle type to determine its rest mass, as demonstrated in William Barletta's lecture notes.

PREREQUISITES
  • Understanding of relativistic physics concepts
  • Familiarity with the equation \(E=c \sqrt{m^2 c^2+p^2}\)
  • Knowledge of particle types and their invariant masses
  • Experience with magnetic spectrometers in particle physics
NEXT STEPS
  • Study the principles of relativistic momentum and energy calculations
  • Learn about the operation of magnetic spectrometers in particle accelerators
  • Explore William Barletta's lecture notes on beam properties for deeper insights
  • Investigate methods for identifying particle types in high-energy physics experiments
USEFUL FOR

Physicists, particle accelerator engineers, and researchers involved in high-energy physics experiments, particularly those focusing on particle identification and energy measurement techniques.

aveline de grandpre
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If i have the momentum of the particle, could I measure their energy ? I'm talking about particles in a beam, they are moving in a relativistic speed.
 
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If you know the momentum you also know the energy,
$$E=c \sqrt{m^2 c^2+p^2},$$
where ##m## is the mass (and mass is the invariant mass and nothing else!) of the particle, and ##p=|\vec{p}|## the three-momentum of the particle.
 
And for very relativistic particles, that is p^2 >> m^2 you have:
E = p \Big[ 1 + \mathcal{O}(\frac{m^2}{2p^2}) \Big]
or that the energy is almost equal to the momentum...

So if you have an electron (m=0.5MeV) that has momentum 1GeV, you can say that its energy is 1GeV... the correction to the energy from the mass will only affect the decimals below 10^{-6} GeV=\frac{ MeV^2}{GeV} which you can check by actually putting numbers in the \sqrt{\text{ }} expression given by vanshees:
E=\sqrt{0.0005^2 + 1^2} GeV = 1.00000025 GeV
 
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If you don't know the particle type (and therefore the mass), measuring energy and momentum would allow calculating it - but that is rarely practical as the energy measurements are not precise enough. Measuring momentum and velocity does work, and it is the main idea how the LHCb detector identifies particles, for example. The energy can be calculated then.
 
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aveline de grandpre said:
If i have the momentum of the particle, could I measure their energy ? I'm talking about particles in a beam, they are moving in a relativistic speed.

In a particle accelerator beam, the momentum is in fact the dynamical variable that you actually measure directly, not energy. This is true when you use, say, a dipole magnet to extract the "energy" and "energy spread" of the particle beam using a magnetic spectrometer. See Pg. 18 of William Barletta's lecture here:

http://uspas.fnal.gov/materials/09UNM/Unit_2_Lecture_4_Beam_Properties.pdf

It is only with the identification of the type of particle (electron, proton, etc... to obtain the rest mass) can you then extract the energy of the particle, using the equations that have been mentioned in this thread, or look on Pg. 17 of the same lecture notes.

Zz.
 
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