Mechanics- connected particles

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Discussion Overview

The discussion revolves around a mechanics problem involving connected particles, specifically focusing on a system of pulleys and masses. Participants explore the relationships between the masses and the lengths of the rope and boxes involved in the setup.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents a problem involving two pulleys and three boxes, asking for the mass of the third box.
  • Another participant suggests that the total length of the rope is 16 m and calculates the mass m to be 7.5 kg.
  • A later reply corrects the previous claim, stating that the textbook answer is 6 kg, indicating a potential error in the trig ratio used.
  • Several participants express confusion about the solution method and request clarification on how to solve the problem.
  • One participant provides a mathematical approach involving a radical equation, leading to a solution for h and confirming it checks out.
  • Another participant expresses gratitude for the clarification and notes a lack of explanation in the textbook regarding similar problems.

Areas of Agreement / Disagreement

There is no consensus on the correct mass of the third box, as participants propose different values (7.5 kg vs. 6 kg) and express confusion about the solution process. The discussion remains unresolved regarding the best approach to the problem.

Contextual Notes

Participants mention issues with understanding the problem and the methods used to solve it, indicating potential gaps in the textbook explanations and the need for further review of radical equations.

Shah 72
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Two smooth pulleys are 8m apart at the same horizontal level. A light inextensible rope passes over the pulleys and a box of mass 5kg hangs at each end of the rope. A third box of mass m kg is attached to the midpoint of the rope and hangs between the pulleys so that all the three boxes are at the same horizontal
16219516208853352424674701945122.jpg
level. The total length of the box is 16m. Find the value of m
 
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total length of the box? … maybe the string length is 16 m ?

if so, I get m = 7.5 kg
 
Last edited by a moderator:
skeeter said:
total length of the box? … maybe the string length is 16 m ?

if so, I get m = 7.5 kg
Iam so so sorry again typo error. Its the total length of the rope = 16m
 
skeeter said:
total length of the box? … maybe the string length is 16 m ?

if so, I get m = 7.5 kg
The ans in the textbook says 6 kg.
 
skeeter said:
total length of the box? … maybe the string length is 16 m ?

if so, I get m = 7.5 kg
Can you pls pls tell me how to work it out?
 
Shah 72 said:
The ans in the textbook says 6 kg.

6 kg is correct … I used the wrong value for a trig ratio.
 
skeeter said:
6 kg is correct … I used the wrong value for a trig ratio.
Can you pls pls tell me the method you worked it out? I have no clue how to solve it.
 
3D285147-A12D-4FFE-868E-957D07107419.jpeg
 
  • #10
$h + \sqrt{h^2+16} = 8$

 
  • #11
skeeter said:
$h + \sqrt{h^2+16} = 8$

By squaring both sides I will get 2h^2=-8 .
 
  • #12
$h + \sqrt{h^2+16} = 8$

$\sqrt{h^2+16} = 8-h$

square both sides …

$h^2+16 = 64 - 16h + h^2$

$16h = 48$

$h =3$

check solution …

$3 + \sqrt{3^2+16} = 3 + 5 = 8$

checks good.

recommend you review solving radical equations …
 
  • #13
skeeter said:
$h + \sqrt{h^2+16} = 8$

$\sqrt{h^2+16} = 8-h$

square both sides …

$h^2+16 = 64 - 16h + h^2$

$16h = 48$

$h =3$

check solution …

$3 + \sqrt{3^2+16} = 3 + 5 = 8$

checks good.

recommend you review solving radical equations …
Thank you so so much! None of these things are explained in the textbook. Iam really struggling with the pulley and string questions. I will surely look into solving radical equations.
 

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