Mechanics- connected particles

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The discussion centers on a mechanics problem involving two smooth pulleys and three boxes, where the total length of the rope is 16 meters. The correct mass of the third box, positioned at the midpoint of the rope, is determined to be 6 kg, contrary to an initial incorrect calculation of 7.5 kg. The solution involves solving the equation \(h + \sqrt{h^2 + 16} = 8\) to find the height \(h\) and confirming the result through substitution. Participants emphasize the importance of accurately applying trigonometric ratios and solving radical equations.

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Two smooth pulleys are 8m apart at the same horizontal level. A light inextensible rope passes over the pulleys and a box of mass 5kg hangs at each end of the rope. A third box of mass m kg is attached to the midpoint of the rope and hangs between the pulleys so that all the three boxes are at the same horizontal
16219516208853352424674701945122.jpg
level. The total length of the box is 16m. Find the value of m
 
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total length of the box? … maybe the string length is 16 m ?

if so, I get m = 7.5 kg
 
Last edited by a moderator:
skeeter said:
total length of the box? … maybe the string length is 16 m ?

if so, I get m = 7.5 kg
Iam so so sorry again typo error. Its the total length of the rope = 16m
 
skeeter said:
total length of the box? … maybe the string length is 16 m ?

if so, I get m = 7.5 kg
The ans in the textbook says 6 kg.
 
skeeter said:
total length of the box? … maybe the string length is 16 m ?

if so, I get m = 7.5 kg
Can you pls pls tell me how to work it out?
 
Shah 72 said:
The ans in the textbook says 6 kg.

6 kg is correct … I used the wrong value for a trig ratio.
 
skeeter said:
6 kg is correct … I used the wrong value for a trig ratio.
Can you pls pls tell me the method you worked it out? I have no clue how to solve it.
 
3D285147-A12D-4FFE-868E-957D07107419.jpeg
 
  • #10
$h + \sqrt{h^2+16} = 8$

 
  • #11
skeeter said:
$h + \sqrt{h^2+16} = 8$

By squaring both sides I will get 2h^2=-8 .
 
  • #12
$h + \sqrt{h^2+16} = 8$

$\sqrt{h^2+16} = 8-h$

square both sides …

$h^2+16 = 64 - 16h + h^2$

$16h = 48$

$h =3$

check solution …

$3 + \sqrt{3^2+16} = 3 + 5 = 8$

checks good.

recommend you review solving radical equations …
 
  • #13
skeeter said:
$h + \sqrt{h^2+16} = 8$

$\sqrt{h^2+16} = 8-h$

square both sides …

$h^2+16 = 64 - 16h + h^2$

$16h = 48$

$h =3$

check solution …

$3 + \sqrt{3^2+16} = 3 + 5 = 8$

checks good.

recommend you review solving radical equations …
Thank you so so much! None of these things are explained in the textbook. Iam really struggling with the pulley and string questions. I will surely look into solving radical equations.
 

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