megavolts61
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Edgardo said:Ok, here's how I calculated 111^3:
111^3 = (111^2)*111 = 12321*111
Calculate 12321*111:
12321*111 = 12321*(100+10+1) = 1232100 + 123210 + 12321
= 13 676 31
I found calculating 12321*111 in my head difficult.
as from my previous reply, you can extend the vedic crisscross method you simple multiply the 12321x 00111
stacking them makes is easier:
12321
00111
so
1x1 is the last digit
2x1 + 1x1 second digit is 3 (no remainder)
then 3x1 + 1x1 + 2x1 = 6 so last three digits are 631.
then add 2x1 + 1x0 + 3x1 + 2x1 = 7 so the last four digits are 7631
then add:
1x1 + 1x0 + 2x1 + 2x0 + 3x1 to get 6 so you have the number ending 67631
then add:
1x1 + 2x0 + 2x1 + 3x0 to get 3 are you seeing a pattern here? now the number ends with 367631
it's getting easier now haha
add:
1x1 + 3x0 + 2x0 = 1 giving you 1367631...if there were not two zeros in the bottom number, you would continue with the last two steps, but in this case there is no need...or you'd wind up with 001367631 which is still 1367631
cheers.
Mike