Method of Pins- Trusses (conceptual)

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SUMMARY

The discussion focuses on the application of the method of joints to analyze a bridge truss design, specifically calculating the tension in each pin under a load of 10,000 lbs. The user is verifying the symmetry of tension across various members, noting that while most tensions are symmetrical, exceptions exist for members GH/HK and FH/HJ. The user confirms that members GH, HK, DG, and KL exhibit compressive forces, indicating a need for careful consideration of load placement on the bridge.

PREREQUISITES
  • Understanding of truss analysis and the method of joints
  • Familiarity with static equilibrium principles
  • Knowledge of tension and compression forces in structural members
  • Proficiency in using Excel for structural calculations
NEXT STEPS
  • Study the method of joints in truss analysis for complex structures
  • Learn about calculating compressive and tensile forces in bridge design
  • Explore the impact of load placement on truss member forces
  • Investigate software tools for structural analysis, such as SAP2000 or RISA
USEFUL FOR

Civil engineers, structural designers, and students studying bridge design and truss analysis will benefit from this discussion, particularly those interested in understanding load distribution and member forces in truss structures.

giacomh
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Homework Statement



I am designing a bridge that looks like this:

http://imgur.com/zFsW7

and using the method of joints to find the tension in each pin. The bridge has to hold 10,000 lbs on each pin, and we have to find the maximum tension in each member (so tension of each member when the weight is on A, then 10,000 B, etc.)

I'm checking my answer by placing the 10,000 lbs on pin I and checking symmetry. (I can't really show work because its in an excel spreadsheet and there are quite a few joints). Every answer is tension is symmetrical except GH/HK and FH/HJ.


Attempt at problem

So, based on summations in the x direction for the pins G and K, GH=DG and HK=KL. So the entire top truss should have equivalent tensions (besides CA and OP)? I don't understand how that works. Will GH=HK no matter where the weight is placed on the bridge?
 
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giacomh said:

Homework Statement



I am designing a bridge that looks like this:

http://imgur.com/zFsW7

and using the method of joints to find the tension in each pin. The bridge has to hold 10,000 lbs on each pin, and we have to find the maximum tension in each member (so tension of each member when the weight is on A, then 10,000 B, etc.)

I'm checking my answer by placing the 10,000 lbs on pin I and checking symmetry. (I can't really show work because its in an excel spreadsheet and there are quite a few joints). Every answer is tension is symmetrical except GH/HK and FH/HJ.


Attempt at problem

So, based on summations in the x direction for the pins G and K, GH=DG and HK=KL. So the entire top truss should have equivalent tensions (besides CA and OP)? I don't understand how that works. Will GH=HK no matter where the weight is placed on the bridge?

Just checking - but you mention the tensions in HK for example.
Did you have a "negative Tension" value - indicating it is actually compression in that member?
 
Yeah, GH, HK, DG, and KL are all compressive
 

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