Mg, N2, O6 Moles: How Many Do You Have?

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Discussion Overview

The discussion revolves around determining the number of moles of each element in the chemical formula Mg(NO3)2 when one mole of the compound is present. The scope includes homework-related queries and conceptual clarifications regarding mole calculations in chemistry.

Discussion Character

  • Homework-related
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant claims to have calculated the moles of Mg, N2, and O6 based on a given mass and molar mass, presenting specific values.
  • Another participant questions the validity of the initial calculations, noting that the numbers were presented without supporting work.
  • A participant provides a formula for calculating moles but later suggests that the method used is inappropriate for this specific question.
  • It is pointed out that there is one atom of magnesium per molecule of Mg(NO3)2, implying that one mole of the compound should result in one mole of magnesium.
  • Another participant clarifies that there are actually two moles of nitrogen atoms in one mole of Mg(NO3)2.
  • A later reply humorously suggests a method of visualizing the problem by counting atoms in a diagram, emphasizing the relationship between moles of a compound and its constituent elements.

Areas of Agreement / Disagreement

Participants express differing views on the calculations and methods used to determine the number of moles of each element, indicating that the discussion remains unresolved with multiple competing perspectives.

Contextual Notes

Some participants highlight the importance of understanding the structure of the compound and the relationship between moles of the compound and its elements, while others focus on the calculation methods. There is no consensus on the correct approach to the problem.

chemistry1
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1. If I have this chemical formula : Mg(NO3)2 and I have one mole of it, how many moles of each element do I have ?
Mg: 0,16mol
N2: 0,19 mol
O6: 0,65 mol

Homework Statement



Would my answer be any good ?
 
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It's hard to tell. You have typed in some numbers without showing any work.
 
Sorry, here it is : Formula n=m/M n=number of moles m=mass in g M=Molar mass

Mg(NO3)2

Mg= 24g
N=14.2=28g
O=16.6= 96

Total= 24+28+96=148g/mol

Mg :24/148=0,16 mol
N2: 28/148=0.19 mol
O6: 96/148=0.65 mol

Would that be enough ? Thanks !
 
If you have one mole of the compound, and if there is one atom of magnesium per compound, then how could you have anything other than one mole of magnesium?
 
You can't use that formula for this particular question. The formula is the actual mass of the molecule divided by the molecular mass of the molecule, which is the mass of 1 mole of a molecule.

For this question, you would simply multiply the number of moles of the molecule by the number of each respective element in the molecule. Since you have 1 Mg, you multiply 1 mole * 1 = 1 mole of Mg in the molecule.
 
Hi chemistry1!
1. If I have this chemical formula : Mg(NO3)2 and I have one mole of it, how many moles of each element do I have ?
In one mole of that compound there are 2 moles of N atoms.
 
Thanks everyone, I understood the logic behind it. :P I was just not viewing it in the right way.
 
If you had only two magnesium nitrate molecules how many atoms of each element would you have? You can just draw this situation on a piece of paper and count up the atoms. For instance you would have something like this on your paper (for two Mg(NO3)2): Mg, Mg, N, N, N, N, O, O, O, O, O, O. Now just do the same for a mole...just kidding but you should be able to see the relationship of number of moles of a given molecule and the number of moles of the constituents of the molecule. It's important to remember that for problems such as these we aren't concerned with structure or anything fancy. You can just as well write MgN2O6 or the long way that I have above and you would be able to work out the problem. The way it is written in the question will give much more information which isn't necessary for this particular problem but which is useful for a Chemist IE we know the anions are nitrates, a well known molecule important in a lot of chemical processes.

A useful exercise may be to do analogous thought experiments with everyday objects you are familiar with. For instance how many tires do 4 cars have? How many steering wheels? how many rearview mirrors? How did you figure that out? How about a mol of cars?
 

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