Minimum value of g for blackhole

[spidey]

escape velocity v = (2gr)^1/2
for black hole,
(2gr)^1/2 > c
g > c^2/2r

Now wat could be the minimum value of g for black hole

 

[Ken G]

There is no limit on g, it's the potential that counts, relative to c²/2. The potential is given classically by g*R, so the constraint is on the product of g and the Schwarzschild radius of the black hole. That's also the ratio of the mass to the radius, or the product of mass and g.