Minimum value of g for blackhole

  • Thread starter spidey
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Main Question or Discussion Point

escape velocity v = (2gr)^1/2
for blackhole,
(2gr)^1/2 > c
g > c^2/2r

Now wat could be the minimum value of g for blackhole
 

Answers and Replies

Ken G
Gold Member
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332
There is no limit on g, it's the potential that counts, relative to c2/2. The potential is given classically by g*R, so the constraint is on the product of g and the Schwarzschild radius of the black hole. That's also the ratio of the mass to the radius, or the product of mass and g.
 
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