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Minimum value of g for blackhole

  1. Mar 20, 2008 #1
    escape velocity v = (2gr)^1/2
    for blackhole,
    (2gr)^1/2 > c
    g > c^2/2r

    Now wat could be the minimum value of g for blackhole
  2. jcsd
  3. Mar 20, 2008 #2

    Ken G

    User Avatar
    Gold Member

    There is no limit on g, it's the potential that counts, relative to c2/2. The potential is given classically by g*R, so the constraint is on the product of g and the Schwarzschild radius of the black hole. That's also the ratio of the mass to the radius, or the product of mass and g.
    Last edited: Mar 20, 2008
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