Missile's trajectory problem

  • Thread starter tnutty
  • Start date
327
1
1. The problem statement, all variables and given/known data

A missile's trajectory takes it to a maximum altitude of 1200 km.
If its launch speed is 6.2 km/s , how fast is it moving at the peak of its trajectory?

2. Relevant equations

K+U = K_o+U_o

U(r) = -GMm/r

3. The attempt at a solution

Alright some people have been telling me its zero. Intuitively thats what I thought, but
I guess its wrong. Nevertheless, here is my attempt :

K+U = K_o +U_o;

=

1/2mV^2 - GM_eM/r_d = 1/2mV_o^2 - GM_em / r_e

and solving for
V^2 = V_o^2 - 2GM_e/r_e + GM_e/r_d

where,
V_o = 6.2km -> 6.2*1000m
G = universal graity = 6.67*10^-11
M_e = mass of earth = 5.98*10^24
r_e = radius of earth = 6.37 * 10^6;
r_d = distance between the object and the center of earth
= 1200km -> 1200*1000m

and my answer is terms of meters
~2400m

so dividing by 1000

and

v_p ~ 24m/s
 

Doc Al

Mentor
44,657
989
Re: Gravity

Alright some people have been telling me its zero. Intuitively thats what I thought, but
I guess its wrong.
Why would you think that? (It may be moving horizontally at the peak.)

Nevertheless, here is my attempt :

K+U = K_o +U_o;

=

1/2mV^2 - GM_eM/r_d = 1/2mV_o^2 - GM_em / r_e
Looks good.

and solving for
V^2 = V_o^2 - 2GM_e/r_e + GM_e/r_d
You left off a factor of 2 in that last term.

where,
V_o = 6.2km -> 6.2*1000m
G = universal graity = 6.67*10^-11
M_e = mass of earth = 5.98*10^24
r_e = radius of earth = 6.37 * 10^6;
r_d = distance between the object and the center of earth
= 1200km -> 1200*1000m
1200km is just the altitude, not the distance to the center of the earth.
 
327
1
Re: Gravity

so is this correct?

Although my formula missed a factor of 2, I still did the calculation with the 2 factored in.
Can you check my calculations?
 

Doc Al

Mentor
44,657
989
Re: Gravity

Did you correct your value of r_d?
 
327
1
Re: Gravity

no, I am not sure why I should. The units wont match.

I converted everything into meter and the final answer into km
 

Doc Al

Mentor
44,657
989
Re: Gravity

The issue is not units, but that you are using r_d = 1200 km. That's the altitude; you need the distance to the center of the earth.
 
327
1
Re: Gravity

so is the distance 1200km + earth's radius?
 
327
1
Re: Gravity

how do I get the distance to the center of the earth of the object?
 
327
1
Re: Gravity

So the distance is 1200 * 1000m + earth's radius
because
1) It they are in both meters.

2) Because the projectory is launched from the earth's surface, or top of the earth?
 

Doc Al

Mentor
44,657
989
Re: Gravity

Good
 
327
1
Re: Gravity

Cool, thanks!
 

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