Modelling electromagnetic wave reflection

niko2000
Messages
50
Reaction score
0
Hi,

I am trying to calculate the power of a reflected electromagnetic field and can't find a physical explanation for a given solution.

I've noticed the following example:

The Plane has a radar for altitude measurement which emmits the power Ptx at the frequency ftx. Calculate the power of the received waves when the plane altitude is h=60m and gamma (reflection) factor of the ground is 0.1.

The solution is Prx = Gtx*Grx((c/ftx)/(4*Pi*2*h))^2*gamma^2

What I don't understand here is why is it appropriate to take 2*h as a radius.

c/fth is the wave length
Gtx and Grx are the gains of the receiver and transmitter
and the factor (4*Pi*r)^2 in the denominator comes from spherical geometry (the sphere with radius r has a surface 4*Pi*r^2 - another 4*Pi comes from gain formula derivation)

The factor gamma is squared because the Poynting vector is a product of Electric and magnetic force and the ground reflects both thus gamma^2.

What I don't understand here is why the radius is set as 2*h.

I tried to solve the problem the following way:

The wave power at the point of collision is proportional to 1/(4*Pi*h)^2. At that point we consider the ground reflets 1/gamma^2 of the power and the reflected power at the receiving point is proportional to 1/(4*Pi*h^2).

I would appreciate if anyone could correct my point of view and explain what's the correct way to model a reflected electromagnetic wave.

Thank you!

Niko
 
Physics news on Phys.org
That isn't the radius, the \lambda / (4\pi r^2) factor is called the space loss factor. In the far field, the source of an electromagnetic wave appears to be like a point source, thus, there is an inherent spreading of the wave over 4\pi r^2 in the same sense as a spherical surface is spreading. r, the distance between source and receiver is taken as 2h because the wave travels h to the ground, and then another distance h back up to the receiver on the plane.

The given equation is the antenna link equation for the far-field, you will find this in any antenna textbook.
 
Last edited:
Thread 'Colors in a plasma globe'
I have a common plasma globe with blue streamers and orange pads at both ends. The orange light is emitted by neon and the blue light is presumably emitted by argon and xenon. Why are the streamers blue while the pads at both ends are orange? A plasma globe's electric field is strong near the central electrode, decreasing with distance, so I would not expect the orange color at both ends.

Similar threads

  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
2
Views
1K
  • · Replies 0 ·
Replies
0
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
3K
Replies
8
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
17
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K