Modified Bessel Equation

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    Bessel Bessel equation
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Discussion Overview

The discussion focuses on the asymptotic behavior of modified Bessel equations with complex order, particularly as the variable x approaches zero. Participants explore the interpretation of limits provided in existing literature and seek clarification on the implications for complex-valued parameters.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant requests information on the asymptotic behavior of modified Bessel equations for small x, specifically for complex order.
  • Another participant cites an approximation for ##I_\alpha(z)## as ##I_\alpha(z) \approx \frac{1}{\Gamma(\alpha+1)}\left(\frac{z}{2}\right)^\alpha## and suggests treating it as an analytic function of ##\alpha## for small z.
  • A further comment questions whether the limits for ##K_{\alpha}## imply that ##\alpha## must be non-zero when considering complex values.
  • Another participant agrees with the interpretation that ##z=0## is a regular singular point and asserts that ##\alpha## should be treated as a parameter, implying it is analytic.

Areas of Agreement / Disagreement

Participants express some agreement on the analytic treatment of ##\alpha##, but there is uncertainty regarding the implications of the limits for complex values of ##\alpha##, indicating that multiple views remain on this aspect.

Contextual Notes

The discussion does not resolve the interpretation of the bounds for complex ##\alpha## or clarify the implications of the regular singular point at ##z=0##.

thatboi
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Hey all,
I wanted to know if anyone knew somewhere I could find the asymptotic behavior for small x (i.e x approaching 0) limit of the modified Bessel equations with complex order. The wikipedia page for Bessel functions (https://en.wikipedia.org/wiki/Bessel_function#Modified_Bessel_functions:_Iα,_Kα) provides a limit when ##|z| \ll \sqrt{\alpha+1}## but in the case of complex-valued ##\alpha## I am not sure how to interpret this bound.
Any assistance would be appreciated.
 
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They give

##I_\alpha(z) \approx \frac{1}{\Gamma(\alpha+1)}\left(\frac{z}{2}\right)^\alpha##

just treat this as an analytic function of ##\alpha## for small z.
 
Paul Colby said:
They give

##I_\alpha(z) \approx \frac{1}{\Gamma(\alpha+1)}\left(\frac{z}{2}\right)^\alpha##

just treat this as an analytic function of ##\alpha## for small z.
For the ##K_{\alpha}## limits, it is defined for ##\alpha=0## and ##\alpha>0##, so for the case of complex ##\alpha##, does this just mean ##\alpha\neq 0##?
 
That’s the way I read it. ##z=0## is a regular singular point and ##\alpha## is just a parameter. So it should be analytic.
 

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