Molarity Calculation for Ba(NO3)2 Solution

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SUMMARY

The discussion focuses on calculating the molarity of a barium nitrate (Ba(NO3)2) solution resulting from the reaction of 250 mL of 0.05 M barium hydroxide (Ba(OH)2) with 200 mL of 0.08 M nitric acid (HNO3). The balanced chemical equation is Ba(OH)2 + 2HNO3 → Ba(NO3)2 + 2H2O. The limiting reagent is identified as nitric acid, resulting in 0.008 moles of Ba(NO3)2, leading to a final molarity of 0.017 M when considering the total volume of the solution.

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Homework Statement



Find the molarity of the solution (salt and any excess reagent after reaction of 250 mL of 0.05 M Ba(OH)2 with 200 mL of 0.08 M HNO3.

Homework Equations


The Attempt at a Solution



I am drawing a blank. Here's the balanced equation

Ba(OH)2 + 2HNO3 ===> 2H2O + Ba(NO3)s

Ba(OH) .0125 moles

2HNO3 .016 moles
 
Last edited:
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Simple stoichiometry, this is a limiting reagent question. Your reaction equation is almost OK (chack barium nitrate formula, but I suppose that's a typo) and is a correct first step to solution.
 
Why can I not edit my own damn post?
 
You can for 30 minutes, or something like that.
 
Borek said:
You can for 30 minutes, or something like that.

Ok, well, Ba(NO3)2, correct?
 
Exactly.

Ba(OH)2 + 2HNO3 -> Ba(NO3)2 + 2H2O

Now try the limiting reagent approach.
 
Borek said:
Exactly.

Ba(OH)2 + 2HNO3 -> Ba(NO3)2 + 2H2O

Now try the limiting reagent approach.

I used the number of moles not grams to find the limiting reagent, which is nitric acid. Only .008 moles of barium nitrate will be formed.

.008 moles/.450 L = .017 M
 
0.008 Ba(NO3)2 is a correct intermediate result. But that's not what you were asked about.
 
Borek said:
0.008 Ba(NO3)2 is a correct intermediate result. But that's not what you were asked about.

Borek
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I know. Check my previous post. I put the molarity of the solution.
 
  • #10
It is not all. Excess reagent is still present in the solution in unchanged form.
 
  • #11
Borek said:
It is not all. Excess reagent is still present in the solution in unchanged form.

Ah. I forgot about that.
 
Last edited:
  • #12
You should list every ion and its concentration separately. EOT for me.
 
  • #13
  • #14
End Of Thread, I believe. Do you understand the answer?
 

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