Calculating Moles Using Volume and Molarity

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SUMMARY

The discussion centers on calculating moles using volume and molarity, specifically for barium nitrate (Ba(NO3)2). The user correctly applies the molarity equation, Molarity = moles/L, to determine the number of moles in 5 mL of a 0.1 M barium nitrate solution. The calculation yields 0.0005 moles, confirming the user's approach is accurate. The chemical reaction provided is Ba(NO3)2 + Na2(SO4) = Ba(SO4) + 2Na(NO3), which is relevant for understanding the context of the moles calculated.

PREREQUISITES
  • Understanding of molarity and its formula (Molarity = moles/L)
  • Basic knowledge of chemical equations and stoichiometry
  • Familiarity with unit conversions, particularly between milliliters and liters
  • Knowledge of the properties of barium nitrate (Ba(NO3)2)
NEXT STEPS
  • Study the concept of stoichiometry in chemical reactions
  • Learn how to balance chemical equations effectively
  • Explore the implications of molarity in solution preparation
  • Investigate the applications of molarity in various chemical calculations
USEFUL FOR

Chemistry students, educators, and anyone involved in laboratory work requiring calculations of moles from volume and molarity.

jubbly
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Homework Statement



Was wondering if I did this right, don't know if I used the right equation.

Equation: Ba(NO3)2 + Na2(SO4) = Ba(SO4) + 2Na(NO3)
Volume of barium nitrate: 5mL
Molarity of Barium nitrate: .1M

Homework Equations



Molarity = moles/L

The Attempt at a Solution



.1M = x/.005L
.1x.005 = x
x= .0005 moles
 
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Looks good.
 

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