Moment of inertia of 2 uniform thin rods

[jisbon]

Homework Statement

Calculate the moment of inertia of 2 uniform thin rods about axis A where the figure belows shows the top view.

Relevant Equations

$I=\frac{1}{12}ml^2$

So to start off, what I will do find the center of mass of each of the rods. So for the top rod, COM is at where y= 0.5 L and COM of the rod at the bottom is at x = 0.5 L. From there, how do I proceed in finding the moment of inertia using parallel axis theorem? Do I simply treat:
$I =\frac{1}{12}ml^2+md^2$
Where d is the distance between the centre of mass and point A for each of the rods respectively? (Whereby d will be 0.5 L - 4/9 L for the bottom rod)

Thanks

 

[haruspex]

Homework Statement: Calculate the moment of inertia of 2 uniform thin rods about axis A where the figure belows shows the top view.
Homework Equations: $I=\frac{1}{12}ml^2$

View attachment 251651

So to start off, what I will do find the center of mass of each of the rods. So for the top rod, COM is at where y= 0.5 L and COM of the rod at the bottom is at x = 0.5 L. From there, how do I proceed in finding the moment of inertia using parallel axis theorem? Do I simply treat:
$I =\frac{1}{12}ml^2+md^2$
Where d is the distance between the centre of mass and point A for each of the rods respectively? (Whereby d will be 0.5 L - 4/9 L for the bottom rod)

Thanks

Yes. What will d be for the other rod?

 

[jisbon]

Yes. What will d be for the other rod?

Will it be $\sqrt(({\frac{3}{9}L)}^2+(0.5L)^2)$?

 

[jisbon]

Solved it. Thanks so much for your guidance