Momentum and Collision help needed (2 questions)

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Homework Help Overview

The discussion revolves around two physics problems related to momentum and collisions. The first problem involves calculating the horizontal force exerted by car tires during braking and determining the coefficient of friction. The second problem concerns the elastic collision of two steel balls and the resultant motion of each ball.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants express difficulty in understanding the application of gravitational acceleration in calculations. There is confusion regarding the correct use of equations for force and momentum. Questions arise about the conservation principles relevant to elastic collisions and the specific formulas needed to solve for velocities.

Discussion Status

Some participants have provided guidance on correcting initial calculations and suggested focusing on conservation laws for the collision problem. However, there remains uncertainty about the next steps in both problems, with multiple interpretations of the requirements being explored.

Contextual Notes

Participants note the absence of friction in the second problem and question how this impacts their approach. There is also mention of potential errors in the initial setup of the first problem, particularly regarding the use of gravitational acceleration.

John Comtoi
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Homework Statement


A car braking will decelerate at .8g. If the car's mass is 1200kg, how much horizontal force does each tire exert on the road? What is the coefficient of friction between the tire and the road?

A 2kg steel ball rolling at 4m/s strikes a stationary 5kg steel ball elastically. What is the resultant motion of each ball? How and why would the collision change if it were elastic?

Homework Equations


F=m*a
Ff=μFN

P1+P2=P3+P4 ?
KE=1/2mv^2 ?

The Attempt at a Solution


I am having a very hard time even understanding where to start here. I started off by multiplying (1200kg)(.8g)(-9.8m/s). I am unfamiliar with the measurement being in g's. How would I factor that into the question? I then divided the number by 4 to reference the tires in the work.

The work i have for the second question is basically me attempting to do the momentum equation in the relevant equations. There is two velocities you have to solve for though and I am unsure on how to progress in this problem. I am fairly sure that I started the question wrong and I should be using a different equation. Some guidance would be appreciated!
 
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John Comtoi said:
I am having a very hard time even understanding where to start here. I started off by multiplying (1200kg)(.8g)(-9.8m/s). I am unfamiliar with the measurement being in g's. How would I factor that into the question?
You did so already, just with two mistakes. Just replace g by its value (and correct units) and you are done.
John Comtoi said:
The work i have for the second question is basically me attempting to do the momentum equation in the relevant equations. There is two velocities you have to solve for though and I am unsure on how to progress in this problem.
Your textbook probably has a formula for both velocities. Otherwise, think which quantities are conserved, and use those.
 
mfb said:
You did so already, just with two mistakes. Just replace g by its value (and correct units) and you are done.Your textbook probably has a formula for both velocities. Otherwise, think which quantities are conserved, and use those.

for question #1, what do u mean by done. Am i done with the problem or am i done with referencing g's in the question? If not, what is the next step?

for question #2, could you elaborate? My knowledge on collisions is iffy at best. What formulas are you talking of for velocity?
 
John Comtoi said:
or question #1, what do u mean by done.
You have multiplied the mass by two accelerations, 0.8g and 9.8m/s2. Does that seem right?
John Comtoi said:
for question #2, could you elaborate?
What else is conserved in an elastic collision?
By the way, the question did not mention any friction in this question, so presumably you should ignore it.
 
John Comtoi said:
for question #1, what do u mean by done. Am i done with the problem or am i done with referencing g's in the question? If not, what is the next step?
F=m*a. You know m and a, I don't see the problem.
Divide it by 4 and you are done.
 

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