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## Homework Statement

Place a golf ball on top of a basketball, and drop the pair from rest so they fall to the ground.The golf ball stays on top of the basketball until the basketball hits the floor. The mass of the golf ball is 0.0459 kg, and the mass of the basketball is 0.587 kg.

a) If the balls are released from a height where the bottom of the basketball is at 1.021 m above the ground, what is the absolute value of the basketball’s momentum just before it hits the ground? Answer calculated: 2.627 kg*m/s

b) What is the absolute value of the momentum of the golf ball at this instant?

Answer calculated: 0.205 kg*m/s

c) Treat the collision of the basketball with the floor and the collision of the golf ball with the basketball as totally elastic collisions in one dimension. What is the absolute magnitude of the momentum of the golf ball after these collisions?

d) Now comes the interesting question: How high, measured from the ground, will the golf ball bounce up after its collision with the basketball? (Hint: do not forget to add the diameter of the basketball, 23.87 cm).

Would like to find how to solve parts c) and d)

## Homework Equations

m1v1 + m2v2(initial)=m1v1 + m2v2(final)

## The Attempt at a Solution

In these equations since momentum is conserved I thought that all of the momentum would just be emitted to the golf ball in the end, with the momentum of the basketball(initial) added to the momentum of the golf ball(initial) giving a total momentum of 2.832 kg*m/s, but that was not the case. Would like a little help on how the momentum would be shown for the gold ball after the collision, with this I could solve part d).