Momentum of two balls collision question

[mvk1]

Two balls of equal mass m undergo a collision. One ball is initially stationary. After the collision, the velocities of the balls make angles of 33° and 43° relative to the original direction of motion of the moving ball. If initial speed of moving ball is 5.4 m/s find the final speed.

What I've done:
In x axis:
M1V1+ M2V2= M1V1’+ M2V2’
M(5.4)+M(0)=M(V1’Cos33)+M(V2’Cos46)
5.4M= M( V1’Cos33+ V2’Cos46)
5.4= V1’Cos33+ V2’Cos46

In the y axis:
0= M1V1’+ M2V2’
0=M(V1’Sin33)-M(V2’Sin46)
(Dividing both sides by M)
0=( V1’Sin 33- V2’Sin46)
0= V1’Sin33- V2’Sin46i don't know what do do after this! please help!

HERES IMAGE OF PROBLEM WITH DIAGRAM:
http://i.imgur.com/NKSeA.jpg

 

[Doc Al]

You have two equations and two unknowns. Solve them simultaneously. Try using the method of substitution. (Use one equation to express V1' in terms of V2'. Then substitute that into the second equation and solve for V2'.)

 

[mvk1]

You have two equations and two unknowns. Solve them simultaneously. Try using the method of substitution. (Use one equation to express V1' in terms of V2'. Then substitute that into the second equation and solve for V2'.)

OMG THANKS YOU SO MUCH I DID IT RIGHT ON MY TEST!
PRETTY INTENSE BUT THANKS SO MUCH!
i found easier to use a,b for v1' and v2' made my life a lot easier