Momentum operator in Schrodinger equation

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Discussion Overview

The discussion centers on the role of the momentum operator in the Schrödinger equation within the framework of non-relativistic quantum mechanics. Participants explore the foundational principles of quantum mechanics, the nature of operators, and the origins of the Schrödinger equation.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants assert that in non-relativistic quantum mechanics, all observable quantities are represented by operators.
  • A participant mentions the commutation relation between momentum and position operators, linking it to the Heisenberg Uncertainty Principle and suggesting that both must be treated as operators for the relation to hold.
  • There is a discussion about the nature of quantum rules or postulates, with some participants expressing curiosity about the derivation of the Schrödinger equation and its foundational assumptions.
  • One participant suggests that the momentum operator's form, derived from de Broglie's work, reflects analogies between classical mechanics and wave mechanics.
  • Another participant argues that while some postulates in quantum mechanics cannot be derived, they allow for the development of coherent systems that can be verified.

Areas of Agreement / Disagreement

Participants express differing views on the nature of quantum postulates and their derivation. While some agree on the foundational role of operators, there is no consensus on the implications of these postulates or the origins of the Schrödinger equation.

Contextual Notes

Participants note that the foundational principles of quantum mechanics are often accepted as axiomatic, leading to discussions about the implications of these assumptions and their verification.

Bose
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Why momentum is replaced by momentum operator in Schrödinger equation ?
 
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A key basic idea in QM is that the commutator of p(momentum) and q(position),

qp - pq = i (The tradition in high energy physics is to use units in which c=1, and h bar=1)

For his equation to hold, both q and p must be operators. Note also that this commutator is responsible for the Heisenberg Uncertainty Principle.

In fact this is an assumption, but a good one, and as basic as it gets. You would benefit from a bit of homework, as suggested by malawi_glenn above.
Regards,
Reilly Atkinson
 
So we have a set of quantum rule or postulate that can not be derived. That will be a bit strange, because then where did Schrödinger get his equation?
 
Bose said:
So we have a set of quantum rule or postulate that can not be derived. That will be a bit strange, because then where did Schrödinger get his equation?

He took one part de Broglie and one part Einstein and mixed it together... on a serious note, [tex]p \mapsto -i \hbar \tfrac{\partial}{\partial x}[/tex] follows from de Broglie's work and is based on analogies between classical mechanics of particles and waves.
 
Last edited:
Bose said:
So we have a set of quantum rule or postulate that can not be derived. That will be a bit strange, because then where did Schrödinger get his equation?

That is not strange, every field has its postulates (axioms) that can't be derived nor be prooved.

However, you may postulate something, then from those axioms derive formulas and relations which can be verified and thus one can tell if you can build up a coherent system (a paradigm) or not.

Here you can read Schrodingers first publication about his new equation:
http://home.tiscali.nl/physis/HistoricPaper/Schroedinger/Schroedinger1926c.pdf

Hanve fun :-)
 
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