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More than two standard deviations away from its mean

  1. Jan 7, 2013 #1
    more than "two standard deviations away from its mean"

    Suppose we need to find the probability that a binomial random variable with n = 100 and p = 0.5 is more than two standard deviations away from its mean and then compare this to the upper bound given by Chebyshev's Theorem.

    What is exactly meant by "more than two standard deviations away from its mean"? How do we exactly solve those kinds of problems? I'm rusty with this, so bear with me.
     
  2. jcsd
  3. Jan 7, 2013 #2

    chiro

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    Re: more than "two standard deviations away from its mean"

    Hey Hiche.

    This means that you are finding P(|X - mu| > 2*sigma) where X is your random variable.
     
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