Motion that changes from constant a to constant v

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SUMMARY

The discussion focuses on a physics problem involving a car and a cyclist accelerating from rest to their respective cruising speeds of 50 mi/h and 20 mi/h with constant accelerations of 9.00 mi/h² and 13 mi/h². The key equations used include the kinematic equations for motion under constant acceleration and constant velocity. The main objectives are to determine the time interval during which the cyclist is ahead of the car and the maximum distance by which the cyclist leads the car. The solution involves analyzing the transitions between three motion regimes: both accelerating, one at maximum speed, and both at maximum speed.

PREREQUISITES
  • Understanding of kinematic equations for motion: X(final)=X(initial) + Vx(t), Vx(final)=Vx(initial)+ax(t), X(final)=x(initial)+V(initial)t+1/2at²
  • Knowledge of constant acceleration and constant velocity concepts
  • Ability to perform unit conversions between miles per hour and other units of acceleration
  • Familiarity with motion regimes and transition analysis in physics
NEXT STEPS
  • Study the application of kinematic equations in problems involving multiple motion regimes
  • Learn how to analyze motion transitions between constant acceleration and constant velocity
  • Explore examples of similar physics problems involving vehicles and cyclists
  • Investigate the effects of varying acceleration rates on the outcomes of motion problems
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, as well as educators looking for examples of motion problems involving acceleration and velocity transitions.

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Homework Statement


As soon as a traffic light turns green, a car speeds up from rest to 50 mi/h with constant acceleration 9.00mi/h*s. In the adjoining bike lane, a cyclist sppeds up from rest to 20 mi/h with constant acceleration 13mi/h*s. Each vechicle maintains constant velocity after reaching its cruising speed. (a) for what time interval is the bicucle ahead of the car? (b) by what maximum distance does the bike lead the car?


Homework Equations


X(final)=X(initial) + Vx(t)
Vx(final)=Vx(initial)+ax(t)
X(final)=x(initial)+V(initial)t+1/2at^2

The Attempt at a Solution



Im not really sure how to do this problem because the objects go from constant acceleration to constant velocity. Here is my guess.
for the bike it is constant a model until Vx is 20mi/h so when t=V(final)/a the bike changes from constant a model to the constant velocity model. So I plugged t into the constant velocity model for the bike getting X(final)=X(initial)+V(V/a). Then since I want to find when car passes bike i set equation 3 equal to the velocity bike model. x(initialcar)+V(initialcar)t+1/2a(car)t^2 = X(initialbike)+V(bike)(V(bike)/a(bike)). Then if i solve for t i should get the time interval for the bike being ahead of the car but I'm not 100%. To find X initial of bike I took equation 3 for t=v(final)/a. Numbers and conversions aren't important to me as learning how to do these types of problems where the object changes from constant A to V or other way around.
 
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You basically have three regimes.

Both accelerating.
One accelerating. One at max.
Both at max.

As you have apparently figured you determine the transitions between the regimes.

To know which equations you need to solve for - i.e. which regime from above - determine also when the slower transitions from acceleration to constant max. If it calculates out further ahead of the faster a one at max speed then you know to use the relationships of the second regime. If it is still behind, then the equations of the last regime, using the initial conditions you've found.
 

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