Moving Clock: Lorentz Factor Calculation

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
Dimani4
Messages
50
Reaction score
0
Hi guys!
I want to thank to all the guys which helping us to understand the beauty and mystery of the relativistic theory.
Here I just want to share the calculation of Lorenz factor for the moving clock in the frame of reference of the "stationary" observer. This time the clock is not perpendicular to the movement but parallel. Here is is.
clock moving.jpg

Written: Time that observer sees (measures) when clock moving in v direction. I did clock with w length between two plates.
clock moving2.jpg
In the end is written: "The "light" time of the moving watch as being seen by observer at the ground.
This time observer at the ground measures with his "ground" watch. Meaning, he will measure "more" time by the factor called Lorentz factor. Every second in his watch will be (sqrt(1-v^2/c^2)) sec in the moving watch.

Thank you.
 
Physics news on Phys.org
Indeed, I strongly suggest you take a look at our LaTeX primer, if you haven't already:

https://www.physicsforums.com/help/latexhelp/

This method has two important advantages:

1. The equations look better (no problems with handwriting style or poor lighting)

2. Responders can quote individual equations by quoting the LaTeX code, which isn't possible if they're embedded in an image (JPEG, GIF, etc.).
 
  • Like
Likes   Reactions: Dimani4