MHB Mutually Exclusive Probabilities: A vs. B

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For events A and B to be mutually exclusive, the sum of their probabilities must equal the probability of their union. Given that the probability of A is 0.3 and B is 0.8, the total probability would be 1.1, which exceeds 1. Therefore, A and B cannot be mutually exclusive. The confusion arises from misunderstanding the definition of mutually exclusive events. In this case, it is clear that A and B cannot occur simultaneously.
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Hey everyone. Question! If the probability of A is .3 and the probability of B is .8, can A and. B be mutually exclusive? This is confusing me!
 
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They can be mutually exclusive if $\displaystyle P(A\cup B) = P(A)+P(B)$

In your case I don't like the chances!
 

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