- #1

Thecla

- 135

- 10

- TL;DR Summary
- What is probability of throwing one six in a throw of pair of dice?

I was trying to calculate the probability of throwing only one six when throwing a pair of dice.

Using the formula for non-mutually exclusive events : P(A)+P(B)-P(A,B) I get 1/6+1/6-1/36=11/36

but when I count all the 36 possibilities on paper I get 10/36 ways of getting only one 6. What am I doing wrong?

Using the formula for non-mutually exclusive events : P(A)+P(B)-P(A,B) I get 1/6+1/6-1/36=11/36

but when I count all the 36 possibilities on paper I get 10/36 ways of getting only one 6. What am I doing wrong?