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What volume of 10N NaOH should be added to 0.1L of 1 M sodium acetate pH 5.5 to change the pH to 6.0.

so I'm assuming that there is also an amount of acetic acid in this solution for it to have an acidic pH right? So is it a buffer?

In which case,

5.5 = 4.76 + log (1M NaOac / x M Oac)

and so x is 0.182 M acetic acid. or .0182 moles

to raise the ph to 6

i'm assuming it will take away a certain amount from acetic acid and add a certain amount to sodium acetate....so...

6 = 4.76 + log( 0.1 + x / 0.0182 - x)

and solving for x gives me 0.01177 moles of NaOH which is 0.001 Liters of 10 M NaOH.

These numbers look awful to me so I feel like I did this wrong. Is this right?