Need help interpreting this C (programming) Code

In summary, the program takes in a single character from the user and categorizes it as an alphabetic character, a digit, or a special character. The if and else if statements check if the character falls within certain ranges, with the last else statement covering all other cases. The confusion about the input of 100 being classified as a digit is due to scanf() only taking in one character.
  • #1
pyroknife
613
4
Code:
// Program to categorize a single character that is entered at the terminal

#include <stdio.h>

int main (void)

{
     char c;

     printf ("Enter a single character:\n");
     scanf ("%c", &c);

     if ( (c >= 'a' && c <= 'z') || (c >= 'A' && c <= 'Z') )
          printf ("It's an alphabetic character.\n");
     else if ( c >= '0' && c <= '9' )
          printf ("It's a digit.\n");
     else
          printf ("It's a special character.\n");

     return 0;
}

Alright so I don't quite get the if and else if statements.

For "else if ( c >= '0' && c <= '9' )" shouldn't that only work for single digit #s? I typed in 100, which set c=100, but the output still gave me "It's a digit." I don't understand why. 100 is >0, but not <9.
 
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  • #2
It's only taking the first character of what you type in, which in your example is 1
 
  • #3
pyroknife said:
I typed in 100, which set c=100.

Don't "guess" the value of c that you read in. Either look at it with a debugger, or print it out.

As PHinds said, you haven't understood what the scanf() call does.
 
  • #4
oh I see. scanf() only takes in one character b/c the input is defined as "char c."
 

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