# Need Help Understanding a Pattern I Found

1. Feb 26, 2009

### Emanresu56

I'm definitely sure this has already been discovered by some mathematician way back, but I just discovered it today.

Here it is:

1+2+3=6
3+4+5=12
5+6+7=18
7+8+9=24

Etc.

What is this called (if it's called anything), and how does it work? And I'm mystified as to how the first numbers in each equation are odd (1, 3, 5, 7), and then there are even numbers (2, 4, 6, 8), and then there are odd numbers (3, 5, 7, 9), and then there are even numbers again (6, 12, 18, 24). Maybe I just inadvertently set it up that way?

Thanks!

2. Feb 26, 2009

### Ben Niehoff

In general, you have

(a-1) + a + (a+1)

simply collect the 1's to get

a + a + a = 3a

So of course, if a is an even number, 3a will be an even number.

3. Feb 26, 2009

### HallsofIvy

You "set it up that way" when you chose the first number to be 1, an odd number. If n is an odd number, say, n= 2k+ 1, then the next number, n+ 1= 2k+1+1= 2k+ 2= 2(k+ 1) is even, and the last, n+2= 2k+1+ 2= 2k+ 2+ 1= 2(k+1)+ 1 is again odd. And by taking the last number on one line as the first number on the second line you have guarenteed that "odd, even, odd" pattern continues.

As for the last column, for n odd, n= 2k+1, n+ (n+1)+ (n+2)= 2k+1+ (2k+2)+ (2k+3)= 6k+ 6= 6(k+1) so the last column is not just even but is always divisible by 6.

4. Nov 16, 2011

### Carl A Bohn

Perhaps a good direction to take your study is into palandromic numbers such as 11,22,33... then 111, 121, 131, ... then 1221, 1331, 1441 and so on. I did wrtie a small fortran routine years ago. but may work better under the control of string manipulation than arithetic.