What is the reaction of the floor of the elevator on the boy?

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    Elevator Reaction
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Homework Help Overview

The discussion revolves around the forces acting on a boy standing in an elevator, specifically focusing on the reaction force from the elevator floor as it accelerates upwards and then moves at a constant velocity. The subject area includes concepts from mechanics, particularly Newton's laws of motion and the effects of acceleration on perceived weight.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between weight, normal force, and acceleration, questioning how these forces change during different phases of the elevator's motion. There are attempts to apply free body diagrams and Newton's laws to understand the forces acting on the boy.

Discussion Status

Some participants have provided insights into the concepts of perceived weight and the effects of acceleration on the normal force. There is an ongoing exploration of how to apply these concepts to the specific questions posed, with various interpretations being discussed.

Contextual Notes

Participants note confusion regarding the application of forces in different scenarios, particularly when the elevator accelerates upwards versus when it moves at a constant velocity. There is also mention of personal experiences in elevators to illustrate the concepts being discussed.

rachael
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8 A boy of mass 65 kg stands on the floor of an elevator.
a What is the weight of the boy?
b What is the reaction of the floor of the elevator on
the boy?
The elevator starts to move upwards with an
acceleration of 1.0 m s–2.
c What is now the reaction of the floor of the elevator
on the boy?
After accelerating upwards for 2.0 s the elevator
continues with a constant upwards velocity.
d What is now the reaction of the floor of the elevator
on the boy?
e What would be the difference to your answer to
part c if the elevator had an acceleration of 1.0 m s–2
downwards?



a. i use w=mg
b.i don't understand y the answer remains the same shouldn't it be ma=mg-N, where mg=650 and ma=65?
c,d,e.i don't get these questions
 
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for part (a) yeah m g=w and for part (b) since there is no acceleration in the problem then mg=N. for (c) now there is an acceleration so draw a free body diagram of the forces acting on the boy? what direction is the acceleration and how does this effect the boy? this will answer (c) and (d) and (e)
 
From your own experience on an elevator, you notice that when the elevator is static, you feel... normal.

When it starts moving up, you feel heavier. After a while you feel normal again. When it's about to stop you feel lighter.

When it starts moving down, you feel lighter. After a while you feel normal again. When it's about to stop you feel heavier.

It is asking you about these concepts. If you feel heavier, indeed you must be "heavier". That is, if you were standing on a scale on the elevator, it would read a weight higher than your usual.

Weight is caused by the reactionary force from whatever it is you are standing on, in this case, the floor of the elevator. While standing, there are two forces acting on you to produce a net force: gravity (pulling downwards) and the floor (pushing upwards). If the elevator is still, acceleration is zero, so what does this say?

Fnet = ma (a = 0)
Fnet = 0

As we discussed, Fnet consists of two forces, gravity and the floor, so:

Fnet = 0
Fnet = Fgrav + Ffloor = 0
Fnet = mg + Ffloor = 0

Can you take it from here?
 
thank you...
 

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