1. The problem statement, all variables and given/known data What mass of iron(3) chloride should be added to 450 ml of 0.132 M CaCl2 to give a solution with final chloride concentration of 0.555M There are a lot of numbers, and I get confused on how to convert it to get mass of iron(3) chloride!! 2. Relevant equations M = n/L 3. The attempt at a solution ? g iron(3) chloride (162.2 g/mol) .450 L of 0.132 M CaCl2 gives 0.0594 mols 0.555 M Cl- = 0.555 mols/L I know the mole to mole ratio we would use is 2:3 but like, i get stuck at trying to start with the right numbers in my dimensional analyst... my attempt: 0.555 mols/ L Cl- * (0.45 L CaCl2) * (3 mols Cl/2molsCl) *(1mol FeCl3/3molsCl ) = 0.12 (which is wrong).