Negative value for time squared in projectile motion

[pluralangel]

Homework Statement

a projectile is launched 40° above the horizontal and lands a vertical distance of 0.943 m below and a horizontal distance of 2.4 m away; what is the initial velocity of the projectile?

Relevant Equations

vy = v sin θ
vx = v cos θ
v = Δd / Δt (constant velocity)
Δd = v1 Δt + 0.5a Δt^2 (uniform acceleration)

hi, so I've been trying to find the initial velocity of this projectile; but i ended up getting a negative value for seconds squared. I've gone over my solution multiple times but don't see where i went wrong. alternatively, was i supposed to take the absolute value of seconds squared?

thanks in advance for any help : )

 

[PeroK]

Which sign are you using for the upwards direction?

 

[pluralangel]

Which sign are you using for the upwards direction?

up would be negative

 

[PeroK]

up would be negative

And your initial velocity in the $y$ direction is?

 

[pluralangel]

And your initial velocity in the $y$ direction is?

ooh, it would have to be negative v1 sin θ ?

 

[pluralangel]

thanks so much ^_^