Neutralization Reaction: Volume of NaOH(aq) Needed to Neutralize H3PO4(aq)

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SUMMARY

The discussion focuses on calculating the volume of 0.350 mol/L NaOH required to neutralize 54.5 mL of 1.31 mol/L H3PO4. The correct stoichiometric relationship is established through the balanced equation H3PO4 + 3 NaOH → 3 H2O + Na3PO4, indicating a 3:1 molar ratio of NaOH to H3PO4. The formula c1v1 = 3c2v2 is used to derive the necessary volume of NaOH, leading to the conclusion that 68 mL is incorrect, and the correct volume is 6.80 x 10^-2 L. Participants emphasize the importance of writing the balanced reaction equation to avoid calculation errors.

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Homework Statement



what volume of 0.350 mol/L NaOH(aq) is required to completely neutralize 54.5 mL of 1.31 mol/L H3PO4(aq)?

Homework Equations



c1v1 = c2v2

The Attempt at a Solution



You would just solve for v2 but I am not getting the right answer for some reason.
 
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Yes, the equation is wrong.

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Elaborate.
 
No, you follow my earlier advice - write reaction equation & read the page linked to.
 
so, 3c1v1 = c2v2

then v1 = c2v2/3c1 ?

This would give me 6.80x10^-2 L.
 
You got it reversed.

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  • #10
68 mL is not a correct volume of NaOH.
 
  • #11
Borek said:
68 mL is not a correct volume of NaOH.

Yes, I learned the hard way.

I wrote the balanced equation of H3PO4 + 3 NaOH -> 3 H2O + Na3PO4

3CnaohVnaoh = Ch3po4Vh3po4

Is this wrong?
 
  • #12
Yes, this is wrong. You got it reversed.

How many moles of NaOH needed to react with one mole of H3PO4? What shoudl be multiplied by three - number fo moles of NaOH, or number of moles of H3PO4?

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  • #13
Borek said:
Yes, this is wrong. You got it reversed.

How many moles of NaOH needed to react with one mole of H3PO4? What shoudl be multiplied by three - number fo moles of NaOH, or number of moles of H3PO4?

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www.titrations.info, www.chemistry-quizzes.info, www.ph-meter.info

The H3PO4. This way you would have a 1:1 ration, correct?
 
  • #14
Hard to say what you mean.

Ratio of 1:1 - what to what?
 
  • #15
If you multiply the H3PO4 by 3, you would have a ratio of 1:1 with NaOH:H3PO4.

So you could write c1v1=3c2v2?
 
  • #16
If 1 is NaOH and 2 is H3PO4 then yes. But you should be more specific, as what you have wrote is ambiguous.

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