SUMMARY
The discussion focuses on calculating the volume of 0.350 mol/L NaOH required to neutralize 54.5 mL of 1.31 mol/L H3PO4. The correct stoichiometric relationship is established through the balanced equation H3PO4 + 3 NaOH → 3 H2O + Na3PO4, indicating a 3:1 molar ratio of NaOH to H3PO4. The formula c1v1 = 3c2v2 is used to derive the necessary volume of NaOH, leading to the conclusion that 68 mL is incorrect, and the correct volume is 6.80 x 10^-2 L. Participants emphasize the importance of writing the balanced reaction equation to avoid calculation errors.
PREREQUISITES
- Understanding of molarity and concentration (mol/L)
- Knowledge of stoichiometry and balanced chemical equations
- Familiarity with titration calculations
- Ability to manipulate algebraic equations
NEXT STEPS
- Study the principles of titration and how to write balanced chemical equations
- Learn about stoichiometric calculations in acid-base reactions
- Explore resources on titration calculations, such as www.titrations.info
- Practice problems involving molarity and volume calculations in neutralization reactions
USEFUL FOR
Chemistry students, educators, and anyone involved in laboratory work related to acid-base titrations and stoichiometric calculations.