MHB New Billboard Dimensions: 4m x (4m + 96cm^2)

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The amusement park plans to install a rectangular billboard where the length is 4m longer than the width, and the area is initially stated as 96cm². However, this area is deemed impossible given the dimensions, leading to the assumption that the area should actually be 96m². To find the dimensions, the equation x(x + 4) = 96 is used, where x represents the width. Solving this equation will yield the correct width and length of the billboard, confirming the area in square meters. The discussion highlights the importance of accurate area measurement in relation to billboard dimensions.
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An amusement park wants to place a new rectangular billboard to inform visitors of their new attractions. Suppose the length of the billboard to be placed is 4m longer than its width and the area is 96cm^2. What will be the length and the width of the billboard?
 
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Solve x(x + 4) = 96 for x (which is the width).
 
The original post said "the area is 96 cm^2". That is impossible if the length is to be "4 m longer than its width". Prove It is assuming that the area is 96 m^2.
 
Thread 'Erroneously finding discrepancy in transpose rule'

Thread 'Erroneously finding discrepancy in transpose rule'

Obviously, there is something elementary I am missing here. To form the transpose of a matrix, one exchanges rows and columns, so the transpose of a scalar, considered as (or isomorphic to) a one-entry matrix, should stay the same, including if the scalar is a complex number. On the other hand, in the isomorphism between the complex plane and the real plane, a complex number a+bi corresponds to a matrix in the real plane; taking the transpose we get which then corresponds to a-bi...
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